Corvette VIN Breakdown

Corvette VIN Breakdown

<p>Corvette VIN breakdown</p><p>Sample shown is for a 2001 model year car.</p><p>Digit Definition</p><p>1st Country of Origin: 1 = USA 2nd Manufacturer: G = General Motors 3rd Make: 1 = Chevrolet 4th/5th Carline/Series: YY = Corvette 6th Body Style: 1 = hardtop, 2 = two door coupe, 3 = two door convertible 7th Restraint Code: 2 = active, manual w/driver and passenger inflatable restraints. 8th Engine Type: G = LS1, S = LS6 9th Check Digit 10th Model Year: 1 = 2001 11th Plant: 5 = Bowling Green KY Last 6 digits Production number for model year (100001 – 135627).</p><p>GM VIN CHECK DIGIT VERIFICATION</p><p>To determine check digit (9th digit) of your GM car, assign numeric values to any letters found in the VIN Code, according to the following table: A = B = C = D = E = F = G = H = 1 2 3 4 5 6 7 8 K = L = M = N = O = P = R = J = 1 2 3 4 5 6 7 9 S = T = U = V = W = X = Y = Z = 2 3 4 5 6 7 8 9 Any numbers in the VIN retain their original value (not replaced). This yields a 17 digit number. </p><p>Then you multiply each of the 17 digits by a set "multiplier". The multiplier associated with each digit is found in this table: </p><p>1st 2nd 3rd 4th 5th 6th 7th 8th Check 8 7 6 5 4 3 2 10 0 11t 12t 13t 14t 15t 16t 17t 10th h h h h h h h 9 8 7 6 5 4 3 2 </p><p>After multiplying each VIN digit by the associated weight - sum each of the 17 products. Divide this total by 11. The remainder is the check digit. (modulus 11) If the remainder is 10, then the check digit is 'X'.</p><p>Here's an example: VIN = 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0 (note '7' is the check digit) VIN Code 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0 Assigned 1 7 1 2 3 5 2 7 7 3 9 1 1 5 5 2 0 Value Multiplier 8 7 6 5 4 3 2 10 0 9 8 7 6 5 4 3 2 Add the (1 x 8) + (7 x 7) + (1 x 6) + ...... + (5 x 4) + (2 x Products 3) + (0 x 2) = 337 Divide 337 by 11 which gives you 30, and a remainder of 7 which is the same as the 9th digit of the VIN.</p><p>GM VIN CHECK DIGIT VERIFICATION</p><p>To determine check digit (9th digit) of your car you need to take the VIN and assign any letters in the VIN with a set value (number) as follows: </p><p>A = 1, B = 2, C = 3, D = 4, E = 5, F = 6, G = 7, H = 8,</p><p>J = 1, K = 2, L = 3, M = 4, N = 5, O = 6, P = 7, R = 9,</p><p>S = 2, T = 3, U = 4, V = 5, W = 6, X = 7, Y = 8, Z = 9</p><p>Any numbers in the VIN remain the same (not replaced) and thus you have a 17 digit number. </p><p>Then you must multiply each of the 17 digits by a set "weight" (multiplier). The weight applied to each digit is as follows: </p><p>1st = 8, 2nd = 7, 3rd = 6, 4th = 5, 5th = 4, 6th = 3, 7th = 2, 8th = 10,</p><p>9th = 0 (check digit), 10th = 9, 11th = 8, 12th = 7, 13th = 6, 14th = 5,</p><p>15th = 4, 16th = 3, 17th = 2 After multiplying each VIN digit by the associated weight - add up the results of all 17 products. Then divide by 11 and the remainder is your check digit. </p><p>If the remained is 10, then the check digit is 'X'. </p><p>Here's an example: VIN = 1G1BL52P7TR115520 (note '7' is the check digit) </p><p>VIN 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0</p><p>Assigned Values 1 7 1 2 3 5 2 7 7 3 9 1 1 5 5 2 0</p><p>Multiplier 8 7 6 5 4 3 2 10 0 9 8 7 6 5 4 3 2</p><p>Add the products: (1 X 8) + (7 X 7) + (1 X 6) ... (0 X 2) = 337</p><p>Divide 337 by 11 which gives you 30, and a remainder of 7 which is the same as the 9th digit of the VIN.</p>

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