Concentration Review Worksheet

Concentration Review Worksheet

<p> Concentration Review Worksheet</p><p>1) If I make a solution by adding 83 grams of sodium hydroxide to 750 mL of water…</p><p> a) What is the molality of sodium hydroxide in this solution?</p><p> b) What is the percent by mass of sodium hydroxide in this solution?</p><p> c) What is the mole fraction of sodium hydroxide in this solution?</p><p>2) If I make a solution by adding water to 35 mL of methanol (CH3OH) until the final volume of the solution is 275 mL…</p><p> a) What is the molarity of methanol in this solution? (The density of methanol is 0.792 g/mL)</p><p> b) What is the percent by volume of methanol in this solution?</p><p>For chemistry help, visit www.chemfiesta.com © 2007 Cavalcade Publishing, All Rights Reserved Concentration Review Worksheet Answers</p><p>1) If I make a solution by adding 83 grams of sodium hydroxide to 750 mL of water…</p><p>To solve problem 1, you need to have calculated for various parts that there are 2.08 moles of NaOH (which has a molar mass of 40 g/mol), that there are 750 grams of water (which has a density of 1 g/mL), and that there are 41.67 moles of water (which has a molar mass of 18 g/mol).</p><p> a) What is the molality of sodium hydroxide in this solution? 2.77 m (2.08 mol / 0.75 kg water)</p><p> b) What is the percent by mass of sodium hydroxide in this solution? 9.96% (found by finding 83 g / 833 g and multiplying by 100%)</p><p> c) What is the mole fraction of sodium hydroxide in this solution? 0.0475 (found by finding 2.08 mol / 43.75 mol) </p><p>2) If I make a solution by adding water to 35 mL of methanol (CH3OH) until the final volume of the solution is 275 mL…</p><p>When solving this problem, you’ll need to calculate that there are 27.72 grams of methanol (from the density), which is equal to 0.866 mol.</p><p> a) What is the molarity of methanol in this solution? (The density of methanol is 0.792 g/mL) 3.15 M (0.866 mol/0.275 L)</p><p> b) What is the percent by volume of methanol in this solution? 12.7% ( (35 mL/275 mL) X 100)</p><p>For chemistry help, visit www.chemfiesta.com © 2007 Cavalcade Publishing, All Rights Reserved</p>

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