<p> Chapter 1</p><p> p 32, delete problem 2a . p. 32, problem 5, replace last sentence with What is the total mass the balloon can lift at 27oC and 1013 hPa?</p><p> p 34, problem 11c): add an additional note </p><p>Chapter 2</p><p> p 72, problem 7a ¶h ¶c ¶ = 1 v ¶v ¶T T ¶V v T T</p><p> p 73, problem 7b 2 ¶ ¶h p 1 ¶u 1 ¶p 1 ¶ u = – 2 – 2 + + ¶T ¶v T v T T ¶v T T ¶T v T ¶T ¶v</p><p> p. 73, problem 7d ¶u ¶p = T – p ¶v T ¶T v</p><p>Chapter 3</p><p> p 83, equation (3.32)</p><p>T dq mc = A dF p q dt where A is the cross-sectional area.</p><p> p 84, replace top line with</p><p> r = m = m v A Dz</p><p> p 83, equation (3.34)</p><p>Td q g F = ∂ q dt cp ∂p p 93, equation (3.54) ¶q ¶q ¶uzўq ў q ¶ k ¶T 1 dq + u j + = + ¶t ¶xj ¶z T ¶z ¶z c dt rcp p p 93, equation (3.56)</p><p>¶q ¶q ¶uzўqў q ¶ k ¶q 1 dF L + u j + = – + E ¶t ¶xj ¶z T ¶z ¶z dz rcp rcp cp</p><p>Chapter 4 p 120, equation (4.53)</p><p> m m m ¶ iT ¶ lT ¶ lT dT = dT + dXl ¶T ¶T ¶X l</p><p>Chapter 5 p 158, problem 7d</p><p>Ҙ r l 4 3 wl = p r n(r) dr r a 3 0</p><p>Chapter 6 p 166 Figure 6.2 is incorrect p 167 equation (6.22c)</p><p>2 L e s dq = c + lv dT p 2 pRdT p. 182 in the equations on this page, change ws to wv p 184, replace the two equations in the middle of the page</p><p>0 = c pd + w t c l dT + d L lvw v - v d dp 0 = c pd + w tc l dT + d L lvw v + 1 + w v g dz ә d h p 190, problem 6 add the following text to the end of the problem Determine your answer analytically. Check it with the thermodynamic chart.</p><p>Chapter 7 p 192, equation (7.3)</p><p> du r – r z ў = g ў d t r ў</p><p>Chapter 8 p 245, problem 5, replace text by:</p><p>5. Cloud drop size distributions are determined from aircraft measurements using a FSSP (Forward Scattering Single Probe) instrument, which determines drop sizes and concentrations by using optical techniques. The FSSP typically gives counts of particles in fifteen different size bins, with r = 1.5 m. These counts can then be converted into concentrations 1.5 m (# cm-3 1.5 m-1) by taking into account aircraft velocity, etc. One dropsize distribution, n(r), determined from the FSSP during the Arctic Stratus Experiment is given below, from the middle of a stratus deck. The values of the droplet radii given at the top of the table represent the average radius of the 1.5 m size bin. p 246, problem 5a, replace last line by ext: volume extinction coefficient for solar (shortwave) radiation (m-1)</p><p>Chapter 9 p 248, equation (9.2)</p><p> rad SW LW 4 FQ 0 = 1 - a 0 F0 + 1 – 1 – e0 F0 - e 0s T 0</p><p> where (1-0) is the surface longwave reflectivity. p 251, equation (9.9)</p><p>2 ' ' 2 ' ' 2 1/2 2 u * = u w 0 + v w 0 = C D u a - u 0</p><p> p 260, equation (9.27) a g rad SH FB 0 = F Q0 + F Q0 – r Llv E + r l c plPr Twa – T0 – gb E – r l P r s0 c p0</p><p>Chapter 12 p 332, equation (12.1a)</p><p>2 4 2 S 1 – a p pr = sT e 4 pr p 335, replace table at top of page</p><p> n an bn 0 1.000110 0 1 0.034221 0.001280 2 0.000719 0.000077</p><p> p 338 equation (12.5)</p><p>Ҙ p cv 0 EI = cv r T dz = T dp 0 g 0 p 245, equation (12.15)</p><p>* hn 2hn 3 – 1 T n = ln 2 + 1 k c I n</p><p>Chapter 13 p. 370, equation (13.29) dt c 3 1 dW l 1 dW i 1 drel 1 drei = r r +r r – 2 – 2 dT0 2 el l dT0 ei i dT0 relrl dT0 reir i dT0</p><p>Chapter 14 p 387, add units in Table 14.1</p><p>Planet mP rP g0 RP P   P0 T0 1023 kg 103 m m s-2 106 m hPa K p 406, equation (14.13)</p><p>1/4 * T 0 = 1 + n T e</p>