Calculate the Mass of 8

Calculate the Mass of 8

<p>KEY 26 1.Calculate the mass of 8.43 x 10 atoms of silver.</p><p>Mass = (# atoms / N) x atomic mass 26 23 5 Mass = (8.43 x 10 atoms / 6.022 x 10 atoms/mol) x 107.9 g/mol = 1.51 x 10 g</p><p>2.What is the mass of 1.48 mol of potassium sulfide, K2S?</p><p>Mass = mol x molar mass </p><p>Molar mass K2S = 2(39.0) + 32.1 = 110.1 g/mol Mass = 1.48 mol x 110.1 g/mol = 163 g</p><p>3.Calculate the molar mass of barium nitrate, Ba(NO3)2.</p><p>Element # atoms atomic mass Ba 1 x 137.3 = 137.3 N 2 x 14.0 = 28.0 O 6 x 16.0 = 96.0 241.3 g/mol</p><p>4.What is the molar mass of nitroglycerin, C3H5(NO3)3?</p><p>Element # atoms atomic mass C 3 x 12.0 = 36.0 H 5 x 1.0 = 5.0 N 3 x 14.0 = 42.0 O 9 x 16.0 = 144.0 227.0 g/mol</p><p>5.What is the molar mass of Al(OH)3?</p><p>Element # atoms atomic mass Al 1 x 27.0 = 27.0 O 3 x 16.0 = 48.0 H 3 x 1.0 = 3.0 78.0 g/mol</p><p>6.What is the molar mass of C12H22O11?</p><p>Element # atoms atomic mass C 12 x 12.0 = 144.0 H 22 x 1.0 = 22.0 O 11 x 16.0 = 176.0 342.0 g/mol 7.Calculate the number of ammonia molecules in 25.0 g of ammonia, NH3.</p><p># molecules = (mass / molar mass) x N</p><p> molar mass NH3 = 14.0 + 3(1.0) = 17.0 g/mol # molecules = (25.0g / 17.0 g/mol) x 6.022 x 1023 molecules/mol = 8.86 x 1023 molecules</p><p>8.Convert: 17.8 g CO2 = ______molecules CO2</p><p># molecules = (mass / molar mass) x N</p><p> molar mass CO2 = 12.0 + 2(16.0) = 44.0 g/mol # molecules = (17.8g / 44.0 g/mol) x 6.022 x 1023 molecules/mol = 2.44 x 1023 molecules</p><p>9.Convert: 0.546 mol AgNO3 = ______g AgNO3</p><p>Mass = mol x molar mass</p><p>Molar mass AgNO3 = 107.9 + 14.0 + 3(16.0) = 169.9 g/mol Mass = 0.546 mol x 169.9 g/mol = 92.8 g</p><p>10.Convert: 2.56 mol N2O = ______molecules N2O</p><p># molecules = mol x N # molecules = 2.56 mol x 6.022 x 1023 molecules/mol = 1.54 x 1024 molecules</p><p>11.Convert: 0.21 mol KCl = ______g KCl</p><p>Mass = mol x molar mass Molar mass KCl = 39.1 + 35.5 = 74.6 g/mol Mass = 0.21 mol x 74.6 g/mol = 15.7 g</p><p>12.Convert: 10.23 g NaBr = ______molecules NaBr</p><p># molecules = (mass / molar mass) x N molar mass NaBr = 23.0 + 79.9 = 102.9 g/mol # molecules = (10.23g / 102.9 g/mol) x 6.022 x 1023 molecules/mol = 5.99 x 1022 molecules</p><p>13.A 14.2-g sample of Ba(NO3)2 contains how many molecules of Ba(NO3)2?</p><p># molecules = (mass / molar mass) x N</p><p> molar mass Ba(NO3)2 = 241.3 g/mol (see problem 3 above) # molecules = (14.2g / 241.3 g/mol) x 6.022 x 1023 molecules/mol = 3.54 x 1023 molecules</p><p>14.A 50.0-g sample of H2O contains how many molecules of water?</p><p># molecules = (mass / molar mass) x N</p><p> molar mass H2O = 2(1.0) + 16.0 = 18.0 g/mol # molecules = (50.0g / 18.0 g/mol) x 6.022 x 1023 molecules/mol = 1.67 x 1024 molecules</p>

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    3 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us