<p> Stoichiometry Review Sheet 1) Balance the following equation and determine the type of reaction that’s taking place. </p><p>____ PbO2 + ____ Na2SO4  ____ Pb(SO4)2 + ____ Na2O Type of reaction: ______</p><p>2) For the reaction above, how much lead (IV) oxide would be required to make 150 grams of sodium oxide? </p><p>3) If you actually made 135 grams of sodium oxide after performing the reaction described in problem 2, what would your percent yield be? Is this answer reasonable? Explain. </p><p>4) If you performed the reaction described in problem 1 using 100 grams of sodium sulfate and 50 grams of lead (IV) oxide, how many grams of sodium oxide would you expect to make? </p><p>5) What was the limiting reactant from problem 4? ______</p><p>6) How much of the excess reactant was left over after the reaction described in problem 4 was performed? Stoichiometry Review Sheet- KEY 1) Balance the following equation and determine the type of reaction that’s taking place. </p><p>1 PbO2 + 2 Na2SO4  1 Pb(SO4)2 + 2 Na2O Type of reaction: Double Displacement</p><p>2) For the reaction above, how much lead (IV) oxide would be required to make 150 grams of sodium oxide? 289 g PbO2</p><p>3) If you actually made 135 grams of sodium oxide after performing the reaction described in problem 2, what would your percent yield be? Is this answer reasonable? Explain. 46.7%; Yes, because anything under 100% is reasonable</p><p>4) If you performed the reaction described in problem 1 using 100 grams of sodium sulfate and 50 grams of lead (IV) oxide, how many grams of sodium oxide would you expect to make? The Limiting Reactant is PbO2 which predicts that 25.9 g Na2O can be made.</p><p>If the Excess reactant, Na2SO4, was used to predict the amount produced in error, then the amount predicted is 43.7 g Na2O.</p><p>5) What was the limiting reactant from problem 4? The Limiting Reactant is Lead (IV) Oxide, PbO2</p><p>6) How much of the excess reactant was left over after the reaction described in problem 4 was performed? 40.7 g Na2SO4</p>