Honors Chemistry Chapter 9, 10, 11 Review Name KEY

Honors Chemistry Chapter 9, 10, 11 Review Name KEY

<p>Honors Chemistry Chapter 9, 10, 11 review Name KEY!!!</p><p>Perform all work on one piece of loose-leaf paper and hand in at the end of the period.</p><p>1. Perform the following conversions:</p><p> a. 78.2 g of Potassium to moles and atoms 2.00 moles, 1.20 x 1024 atoms</p><p> b. 3.00 moles of Carbon dioxide to liters, molecules, and grams 67.2 L, 1.81 x 1024 molecules, 132 g</p><p> c. 1.20 x 1024 molecules of Fluorine to grams, moles, and liters 75.7 g, 1.99 moles, 44.7 L</p><p> d. 6.02 x 1023 atoms of oxygen to molecules of oxygen 3.01 x 1023 molecules</p><p> e. 6.02 x 1023 atoms of oxygen to molecules of ozone (look up its formula) 2.01 x 1023 molecules</p><p>2. Why can’t you convert g of Potassium to liters? Why can you convert moles of carbon dioxide and molecules of Fluorine to liters? Potassium is not a gas – it’s a solid – 22.4 L/mole is a conversion for gases only. You can convert CO2 and F2 to liters because they are gases.</p><p>3. Calculate the % composition of each atom in CSCl2. C = 10.4%, S = 27.9%, Cl = 61.7%</p><p>4. If a compound is decomposed and yields 2.40 g of carbon, 3.20 g of oxygen, and 0.400 g of hydrogen, what is the empirical formula. What is the molecular formula if the molar mass is 60.0 g/mole? % composition = 40.0 % C, 53.3 % O, H = 6.7% so empirical formula = CH2O, molecular formula = C2H4O2 </p><p>5. Write balanced formula equations that represent the following reactions. Include heat and symbols (phases) in your equations.</p><p> a. The combustion of pentane (C5H12) – exothermic</p><p>C5H12(g) + 8 O2(g) → 5 CO2(g) + 6 H2O(g) + heat</p><p> b. The reaction of aluminum chloride with silver nitrate (neglect heat)</p><p>AlCl3(aq)) + 3 AgNO3(aq) → 3 AgCl(s) + Al(NO3)3(aq)</p><p> c. The reaction of H2SO4 with Iron (III) hydroxide (exothermic)</p><p>3 H2SO4(aq) + 2 Fe(OH)3 (aq) → Fe2(SO4)3 (aq) + 6 H2O(l) + heat</p><p> d. The reaction of sodium hydroxide with HCl (exothermic)</p><p>NaOH (aq) + HCl (aq) → NaCl (aq) + H2O (l) + heat</p><p> e. The synthesis of Aluminum oxide (endothermic)</p><p>4 Al (s) + 3 O2(g) + heat → 2 Al2O3 (s)</p>

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