Learning Goal: To Be Able To Interpret Potential Energy Diagrams And Predict The Corresponding Motion Of A Particle

Learning Goal: To Be Able To Interpret Potential Energy Diagrams And Predict The Corresponding Motion Of A Particle

<p>Learning Goal: To be able to interpret potential energy diagrams and predict the corresponding motion of a particle.</p><p>Potential energy diagrams for a particle are useful in predicting the motion of that particle. These diagrams allow one to determine the direction of the force acting on the particle at any point, the points of stable and unstable equilibrium, the particle's kinetic energy, etc. </p><p>Consider the potential energy diagram shown. The curve represents the value of potential energy as a function of the particle's coordinate . The horizontal line above the curve represents the constant value of the total energy of the particle . The total energy is the sum of kinetic ( ) and potential ( ) energies of the particle.</p><p>The key idea in interpreting the graph can be expressed in the equation</p><p> where is the x component of the net force as function of the particle's coordinate . Note the negative sign: It means that the x component of the net force is negative when the derivative is positive and vice versa. For instance, if the particle is moving to the right, and its potential energy is increasing, the net force would be pulling the particle to the left.</p><p>If you are still having trouble visualizing this, consider the following: If a massive particle is increasing its gravitational potential energy (that is, moving upward), the force of gravity is pulling in the opposite direction (that is, downward).</p><p>If the x component of the net force is zero, the particle is said to be in equilibrium. There are two kinds of equilibrium:</p><p> Stable equilibrium means that small deviations from the equilibrium point create a net force that accelerates the particle back toward the equilibrium point (think of a ball rolling between two hills).  Unstable equilibrium means that small deviations from the equilibrium point create a net force that accelerates the particle further away from the equilibrium point (think of a ball on top of a hill).</p><p>In answering the following questions, we will assume that there is a single varying force acting on the particle along the x axis. Therefore, we will use the term force instead of the cumbersome x component of the net force. 1. The force acting on the particle at point A is ______. directed to the right directed to the left equal to zero F=-dU/dx < 0 at A</p><p>2. The force acting on the particle at point C is ______. directed to the right directed to the left equal to zero F=-dU/dx > 0 at C</p><p>3. The force acting on the particle at point B is ______. directed to the right directed to the left equal to zero F=-dU/dx = 0 at B</p><p>4. If the particle is located slightly to the left of point B, its acceleration is ______. directed to the right directed to the left equal to zero F = -dU/dx =m*a<0 at the left of B 5. Name all labeled points on the graph corresponding to unstable equilibrium. List your choices alphabetically, with no commas or spaces; for instance, if you choose points B, D, and E, type your answer as BDE. BF Because dU/dx is zero at these two points but if the particle is moved slightly away these points, they can not go back to these equilibrium points.</p><p>6. Name all labeled points such that when a particle is released from rest there, it would accelerate to the left. List your choices alphabetically, with no commas or spaces; for instance, if you choose points B, D, and E, type your answer as BDE. AE F = -dU/dx =m*a<0 at these two points</p><p>7. Consider points A, E, and G. Of these three points, which one corresponds to the greatest magnitude of acceleration of the particle? A E G F = -dU/dx =m*a </p><p>8. If the total energy of the particle is known, one can also use the graph of to draw conclusions about the kinetic energy of the particle since </p><p>.</p><p>As a reminder, on this graph, the total energy is shown by the horizontal line.</p><p>What point on the graph corresponds to the maximum kinetic energy of the moving particle? D The lowest potential energy point will corresponds to the maximum kinetic energy point.</p><p>9. At what point on the graph does the particle have the lowest speed? B</p>

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    3 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us