<p> P H Y S I C S E Q U A T I O N S</p><p>1st SEMESTER 2nd SEMESTER Constant Velocity Variables (units) Energy, Work, & Variables (units) v = x/t ∆ = change in Power PE = potential energy (J) a = 0 m/s2 v = velocity (m/s) PE = mgh KE = kinetic energy (J) 2 Changing Velocity v1 = initial velocity KE = ½ mv W = work (J) a = ∆v/t d = distance (m) W = Fd P = power (W( t = time (s) P = W/t J = Joules ∆v = v2 – v1 x = 0.5at2 x = height (m) W = Watts (J/s) 2 v = at a = acceleration, (m/s ) Waves & Variables (units) g = -9.8 m/s2 Light T = 1/f T = period (s) Forces Variables (units) f = 1/T f = frequency (Hz) F = ma F = force (N) v = f  = wavelength (m) c = speed of light, m1a1 = -m2a2 Ff = friction force (N) vsound = 340 m/s 3 × 109 m/s F = G m1m2 n = normal force (N) n1sinΘ1 = n2sinΘ2 r2 m = mass (kg) v1sinΘ1 = v2sinΘ2 n = index of refraction 2 v = speed of light (m/s) Ff = μn N = Newton, (kgm/s ) G = 6.67×10-11 Nm2/kg2 Θ = angle of refraction</p><p>Circular motion Variables (units) Electrostatics Variables (units) 9 2 2 v = 2πr F = kQ1Q1 k = 9 × 10 Nm /C T π = pi r2 Q = charge (C) a = v 2 C = Coulombs r r = radius (m) Momentum & Variables (units) Circuits Variables (units) Impulse I = Q/t I = current, (A) p = mv p = momentum (kgm/s) V = IR V = voltage (V) I = Ft = ∆mv I = impulse (Ns) P = IV R = resistance (Ω) Req = R1 + R2 + R3 P = power (W) Torque Variables (units) 1 = 1 + 1_ + 1 _ . A = amperes, (C/s) τ = F•d τ = torque (Nm) Req R1 R2 R3 Math Reminders Pythagorean Theorem: a2 + b2 = c2 PEMDAS KHDBDCM SOHCAHTOA </p><p>Do you DiTEST problem solving?? D—diagram the problem, identify the variables T—target! What are you solving for? E—equations! Which equations do you need? S—solve! Don’t for get to include units! T—ta da! Does your answer make sense? Check your work! P H Y S I C S E Q U A T I O N S</p>