8) the Ratio Of

8) the Ratio Of

<p> 3 1 8) The ratio of 5to 2 5 10</p><p>Solution:</p><p>3 5 = 28/5 5</p><p>1 2 = 21/10 10</p><p>Ratio = 28/5 : 21/10 = 28 : 21/2 = 56 : 21 </p><p>Divide by 7: Ratio = 8:3</p><p>24) The ratio of 7 dimes to 3 quarters.</p><p>Solution:</p><p>7 dimes = 70 cents</p><p>3 quarters = 75 cents</p><p>Ratio = 7 dimes : 3 quarters = 70:75 = 14:15 (by dividing by 5) 34) Marc took 3 hours (h) to mow a lawn while Angelina took 150 minutes (min) to mow the same lawn a week earlier. Write the ratio of Marc’s time to Angelina’s time as a ratio of whole numbers.</p><p>Solution:</p><p>Convert Marc’s time in minutes.</p><p>Marc's time = 3 hours = 3 * 60 minutes = 180 minutes</p><p>Angelina's time = 150 minutes</p><p>Ratio = Marc's time : Angelina's time = 180 : 150 = 6 : 5</p><p>14) Find the rate 240 poundsoffertilizer 6lawns</p><p>Solution:</p><p>6 lawns cost 240 pounds of fertilizer.</p><p>1 lawn would cost = 240/6 pounds = 40 pounds</p><p>Rate = 40 pounds of fertilizer per lawn.</p><p>30) Which is the better buy: 5 lb of sugar for $4.75 or 20 lb of sugar for $19.92?</p><p>Solution:</p><p>Rate of 5 lb of sugar for $4.75: 4.75/5 = $0.95 per pound</p><p>Rate of 20 lb of sugar for $19.92: 19.92/20 = $0.996 per pound</p><p>Since $0.95 < $0.996, Thus 5 lb of sugar for $4.75 is a better buy.</p><p>10) Write the proportion that is equivalent to the given statement</p><p>If Maria hit 8 home runs in 15 softball games, then she should hit 24 home runs in 45 games.</p><p>Solution:</p><p>Equivalent proportion will be</p><p>8/15 = 24/45</p><p>28) Determine whether each pair of fractions is proportional</p><p>5 75 = 8 120 Solution: Cross multiply:</p><p>5*120 = 600</p><p>8*75 = 600</p><p>Both are equal thus fractions are proportional.</p><p>48) Determine if the given rates are equivalent</p><p>12gallons 9 gallons = 8,329ft2 1,240 ft 2</p><p>Solution:</p><p>Cross-multiply:</p><p>12*1240 = 14880</p><p>9*8329 = 74961</p><p>They are different, therefore fractions are not equivalent.</p><p>16) A store has T-shirts on sale at 2 for $5.50. At this rate, what do five T-shirts cost?</p><p>Solution:</p><p>Let x be the cost of five T-shirts. Then proportion will be</p><p>5.50 x  2 5 x  $13.75</p><p>The cost of five T-shirts is $13.75. Activity Cal/h Activity Cal/h Bicycling 6 mi/h 240 Running 10 mi/h 1,280 Bicycling 12 mi/h 410 Swimming 25 yd/min 275 Cross-country skiing 700 Swimming 50 yd/min 500 Jogging 5 mi/h 740 Tennis (singles) 400 Jogging 7 mi/h 920 Walking 2 mi/h 240 Jumping rope 750 Walking 3 mi/h 320 Running in place 650 Walking 4 mi/h 440</p><p>For problems 1 through 4, assume a 150-pound person 1 1 1) If a person jogs at a rate of 5 mi/h for 3 h in a week, how many calories do they 2 2 burn? Solution:</p><p>Jogging at that rate burns 740 calories per hour.</p><p>Multiply that by 3 ½ = 3.5 hours:</p><p>Calories burnt = 740*3.5 = 2590 calories</p><p>2) If a person runs in place for 15 minutes, how many calories will be burned?</p><p>Solution:</p><p>You burn 650 calories an hour.</p><p>15 minutes = ¼ of an hour</p><p>Calories burnt = ¼ * 650 = 162.5 calories 3) If a person cross-country skis for 35 minutes, how many calories will be burned? Solution:</p><p>Calories burnt 700 calories per hour</p><p>35 minutes = 35 / 60 hours = 7/12 hours</p><p>Calories burnt in 35 minutes = 7/12 * 700 = 408.33 calories</p><p>4) How many hours would a person have to jump rope in order to lose 1 pound? (Assume calorie consumption is just enough to maintain weight, with no activity.)</p><p>Solution:</p><p>Jumping rope is 750 calories per hour.</p><p>You need to burn 3500 cals to lose a pound:</p><p>2 Number of hours = 3500 / 750 = 4 hours = 4.67 hours 3</p><p>Heavier people burn more calories (for the same activity), and lighter people burn fewer. In fact, you can calculate similar figures for burning calories by setting up the appropriate proportion</p><p>5) At what rate would a 120-pound person, burn calories while bicycling at 12 mi/h?</p><p>A 150 pound person burns 410 cal per hour.</p><p>Let x be the rate.</p><p>Then proportion will be</p><p>150/410 = 120/x Cross multiply:</p><p>150x = 120*410</p><p>Divide by 150: x = 120*410/150 = 328 cal/hr</p><p>6) At what rate would a 180-pound person, burn calories while bicycling at 12 mi/h?</p><p>Solution:</p><p>Let x be the rate.</p><p>Then proportion will be</p><p>150/410 = 180/x</p><p>Cross multiply:</p><p>410*180 = 150x</p><p>Divide by 150: x = 410*180/150 x = 492 cal/hr</p><p>Rate is 492 cal/hr.</p><p>7) How many hours of jogging at 5 mi/h would be needed for a 200-pound person to lose 5 pounds? (Again, assume calorie consumption is just enough to maintain weight, with no activity.) Solution:</p><p>A 150 pound person burns 740 cal/hr</p><p>Proportion will be</p><p>150/740 = 200/x</p><p>Cross multiply:</p><p>150x = 200*740 x = 740*200/150 x = 986.67 cal/hr</p><p>5 pounds * 3500 cal/pound = 17500 calories need to be burned</p><p>17500 No. of hours =  17.74 hours 986.67</p>

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