<p> Magdy Essafty – [email protected] 1 الرد على موضوع سؤال فى الحتمالت </p><p>اسم العضو : مجدى الصفتى </p><p>Question 1 If A and B are independent events Then P ( A ∩B ) = P ( A ) . P ( B ) To prove that : A, B are independent events we must prove : P ( A ∩B ) = P ( A) . P ( B ) Since : P ( A ∩B ) = 1 – P ( A B ) P ( A ∩B ) = 1 – P ( A ) – P ( B ) + P ( A ∩B ) P ( A ∩B ) = 1 – P ( A ) – P ( B ) + P ( A ) . P ( B ) P ( A ∩B ) = [ 1 – P ( A ) ] – P ( B ) [ 1 – P ( A ) ] P ( A ∩B ) = [ 1 – P ( A ) ] . [ 1 – P ( B ) ] P ( A ∩B ) = P ( A) . P ( B ) Therefore A, B are independent events.</p><p>Question 2 S = { ( w , w , w , w ) , ( l , l , l , l ) , ( w , w , w , l ) , ( w , w , l , w ) , ( w , l , w , w ) , ( l , w , w , w ) , ( l , l , l , w ) , ( l , l , w , l ) , ( l , w , l , l ) , ( w , l , l , l ) , ( w , w , l , l ) , ( l , l , w , w ) , ( w , l , l , w ) , ( l , w , w , l ) , ( w , l , w , l ) , ( l , w , l , w ) } Range of the random variable: { 4 , 3 , 2 , 1 , 0 } The probability distribution: </p><p>X r 4 3 2 1 0 1 1 3 1 1 f ( X r ) 16 4 8 4 16 Magdy Essafty – [email protected] 2 الرد على موضوع سؤال فى الحتمالت </p><p>اسم العضو : مجدى الصفتى </p><p>The expectation 1 1 3 1 1 = 4 + 3 + 2 + 1 + 0 = 2 16 4 8 4 16 The variance 1 1 3 1 1 2 = 16 + 9 + 4 + 1 + 0 = 5 16 4 8 4 16</p><p>Question 3</p><p> = 250 , = 6 240 250 P ( x 240 ) = P ( z ) 6</p><p>P ( z - 1.67 ) = P ( z 1.67 ) = 0.5 – 0.4525 = 0.0475</p><p>Question 4</p><p>ىىى ىىى ىىىىى ىىىىىىىى ىى ىىىىىى ىىىىىى : </p><p>10 7 3 C 3 C 4 C 3 = 4200</p><p>ىىى ىىى ىىىىى ىىىىىىىى ىى ىىىىىى ىىىىىى : </p><p>3 7 3 C 3 C 4 C 3 = 35 مع تحياتى للجميع </p>
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