<p> Chapter 3 Mass Relationships in Chemical Reactions</p><p>3.1 Atomic Mass · the mass of the atom in atomic mass units (amu) · atomic mass unit - · Average Atomic Mass · most naturally occurring elements have more than one isotope · relative atomic masses are weighted averages (of natural abundances) of all the isotopes of an element Example: Boron exists as two naturally occurring isotopes: 20.0% 10.01 amu, 80.0% 11.01 amu</p><p>3.2 Avogadro’s Number and the Molar Mass of an Element · mole (mol) - the amount of substance that contains as many elementary entities (atoms, molecules, or other particles) as there are atoms in exactly 12 grams of the carbon-12 isotope · This number is called Avogadro’s Number = 6.022045 1023 particles · · molar mass (gram-molar mass)(atomic mass)(gram- atomic mass) - the mass of Avogadro’s number of units</p><p>1 1 mol C = 12.00 g C = 6.022 1023 atoms of C 1 mol S = 32.07 g S = 6.022 1023 atoms of S</p><p> What is the mass of 72 atoms of sulfur?</p><p>3.3 Molecular Mass the sum of the atomic masses (in amu) in the molecule · molar mass (gram-molecular mass) - molecular mass expressed in grams - one mole of a compound - 6.022 1023 molecules</p><p> How many moles of sucrose (C12H22O11) are contained in 8.76 g of sucrose?</p><p>3.4 Mass Spectrophotometer</p><p>2 (see figure 3.3)</p><p>3.5 Percent Composition of Compounds percent composition by mass - percent by mass of each element in a compound</p><p> Calculate the mass % of carbon in vitamin C, C3H4O3</p><p> Calculate the empirical formula of a compound having the following composition: 26.56% K, 35.41% Cr, 38.03% O</p><p>3 Calculate the mass of chromium contained in 548 g of potassium dichromate.</p><p>3.6 Experimental Determination of Empirical Formulas combustion analysis:</p><p>[CHX] + O2 CO2 + H2O</p><p> An unknown compound is composed of carbon, hydrogen, and oxygen. When 5.000 g is subjected to combustion analysis, 11.879 g of CO2 and 6.075 g of H2O </p><p>4 are produced. Calculate its empirical formula.</p><p>· Determination of Molecular Formulas A certain compound has a formula mass of approximately 42 g. Find its molecular formula if it is composed of 85.64% C and 14.36% H.</p><p>3.7 Chemical Reactions and Chemical Equations · Writing Chemical Equations reactants and products · Balancing Chemical Equations</p><p>5 3.8 Amounts of Reactants and Products stoichiometry - the quantitative study of reactants and products in a chemical reaction The coefficients of a balanced equation represent numbers of moles of reactants and products.</p><p> What mass of sodium chloride will be produced by the decomposition of 50.0 g of sodium chlorate?</p><p>6 How many grams of sodium are required to react with excess water to produce 25.0 g of sodium hydroxide?</p><p> How many molecules of chlorine gas are needed to react with 10.0 g of sodium to produce sodium chloride?</p><p>3.9 Limiting Reagents</p><p> What mass of sodium sulfate would be formed by the reaction of 32.0 g of sodium hydroxide and 41.3 g of sulfuric acid?</p><p> What is the minimum amount of P4S3 that would have to be burned to produce at least 3.00 g of P4O10 and 3.00 g of SO2?</p><p>P4S3 + O2 P4O10 + SO2</p><p>7 3.10 Reaction Yield</p><p>· actual yield - the amount of product obtained in a reaction · theoretical yield - the amount of product predicted by stoichiometry when all the limiting reagent has reacted · percent yield - the proportion of the actual yield to the theoretical yield</p><p>8</p>
Details
-
File Typepdf
-
Upload Time-
-
Content LanguagesEnglish
-
Upload UserAnonymous/Not logged-in
-
File Pages8 Page
-
File Size-