Angle Bisectors in a Quadrilateral Are Concurrent

Angle Bisectors in a Quadrilateral Are Concurrent

Angle Bisectors in a Quadrilateral in the classroom A Ramachandran he bisectors of the interior angles of a quadrilateral are either all concurrent or meet pairwise at 4, 5 or 6 points, in any case forming a cyclic quadrilateral. The situation of exactly three bisectors being concurrent is not possible. See Figure 1 for a possible situation. The reader is invited to prove these as well as observations regarding some of the special cases mentioned below. Start with the last observation. Assume that three angle bisectors in a quadrilateral are concurrent. Join the point of T D E H A F G B C Figure 1. A typical configuration, showing how a cyclic quadrilateral is formed Keywords: Quadrilateral, diagonal, angular bisector, tangential quadrilateral, kite, rhombus, square, isosceles trapezium, non-isosceles trapezium, cyclic, incircle 33 At Right Angles | Vol. 4, No. 1, March 2015 Vol. 4, No. 1, March 2015 | At Right Angles 33 D A D A D D E G A A F H G I H F F G E H B C E Figure 3. If is a parallelogram, then is a B C B C rectangle B C Figure 2. A tangential quadrilateral Figure 6. The case when is a non-isosceles trapezium: the result is that is a cyclic Figure 7. The case when has but A D quadrilateral in which : the result is that is an isosceles ∘ trapezium ( and ∠ ) E ∠ ∠ ∠ ∠ concurrence to the fourth vertex. Prove that this line indeed bisects the angle at the fourth vertex. F H Tangential quadrilateral A quadrilateral in which all the four angle bisectors G meet at a pointincircle is a — one which has an circle touching all the four sides. This A RAMACHANDRAN has had a long standing interest in the teaching of mathematics and science. He studied incentre B C physical science and mathematics at the undergraduate level, and shifted to life science at the postgraduate circle is the of the quadrilateral, and its level. He taught science, mathematics and geography to middle school students at Rishi Valley School for over centre is the of the quadrilateral (see two decades, and now stays in Chennai. His other interests include the English language and Indian music. He Figure 4. If is a rectangle, then is a Figure 2). Prove that in such a quadrilateral the may be contacted at [email protected]. square sums of the lengths of opposite sides are equal (i.e., in Figure 2, ). Also prove the converse: If the sums of the lengths of opposite A D sides of a quadrilateral are equal, the quadrilateral is tangential. Special cases of tangential quadrilaterals are the E kite and rhombus (including the square). In the F H former, one diagonal bisects the angles at the G vertices it joins, while this is true of both diagonals in a rhombus. B C In the case of the bisectors meeting pairwise they form a quadrilateral. Prove that this is cyclic. Also prove the following: Figure 5. If is an isosceles trapezium with opposite side sums unequal, then is a cyclic kite (1) The angle bisectors in a general parallelogram form a rectangle (see Figure 3). (2) The angle bisectors in a general rectangle form a square (see Figure 4). (4) In the case of a quadrilateral with only one set of opposite angles equal (opposite side sums (3) The angle bisectors in an isosceles trapezium unequal), the angle bisectors form an isosceles (opposite side sums unequal) form a cyclic trapezium (see Figure 7). kite (also called a ‘right kite’), where the equal Remark. angles are right angles (see Figure 5). We see from this survey that the simple The case of a non-isosceles trapezium is act of drawing the internal bisectors of the four shown in Figure 6. Here we get a quadrilateral angles of a quadrilateral produces a con�iguration in which one pair of opposite angles are right that offers unexpected riches. We invite the angles. reader to supply proofs for the many claims made. 3534 At Right Angles | Vol. 4, No. 1, March 2015 Vol. 4, No. 1, March 2015 | At Right Angles 3534 2 At Right Angles ∣ Vol. 4, No. 1, March 2015 Vol. 4, No. 1, March 2015 ∣ At Right Angles 3 A D D G A G H F F E H E B C B C Figure 6. The case when is a non-isosceles trapezium: the result is that is a cyclic Figure 7. The case when has but quadrilateral in which : the result is that is an isosceles ∘ trapezium ( and ∠ ) ∠ ∠ ∠ ∠ A RAMACHANDRAN has had a long standing interest in the teaching of mathematics and science. He studied physical science and mathematics at the undergraduate level, and shifted to life science at the postgraduate level. He taught science, mathematics and geography to middle school students at Rishi Valley School for over two decades, and now stays in Chennai. His other interests include the English language and Indian music. He may be contacted at [email protected]. C Challenge! Can you find the radius of the inscribed circle C ? 1 The two quarter circles (centred at the two bottom vertices of the 1× 1 square square) have radius 1 unit each. 1 Can you find the radius of the inscribed circleC ? The two quarter circles (centred at the two bottom vertices of the square) have radius 1 unit each. 35 At Right Angles | Vol. 4, No. 1, March 2015 Vol. 4, No. 1, March 2015 | At Right Angles 35 Vol. 4, No. 1, March 2015 ∣ At Right Angles 3.

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