HAUSDORFF MEASURES & APPLICATIONS 1. Preliminaries

HAUSDORFF MEASURES & APPLICATIONS 1. Preliminaries

HAUSDORFF MEASURES & APPLICATIONS Abstract. The Hausdorff measure is a generalisation of the Lebesgue measure to an arbitrary metric space. This paper will investigate the s-dimensional Hausdorff measure on RN and discuss some of the applications that arise, including the Area and Co-Area For- mulae. 1. Preliminaries Recall the definition of the Lebesgue (outer) measure of A ⊆ RN : ( 1 ) X [ mN (A) := inf vol Rj : A ⊆ Rj;Rj open rectangles j=0 j2N This generalises the familiar notions of length, area and volume to N dimensions. However, the Lebesgue measure has no way to assign N- dimensional measure to A ⊆ RM where M 6= N. To see how we might be able to construct a measure which can deal with this problem, we first need to decide what N-dimensional measure in RM might mean. Certainly rectangles will not be helpful here, so to start with we need to know the Lebesgue measure of another class of sets. πs=2 Lemma 1.1. Let α(s) := s . Γ( 2 + 1) For all N ≥ 1, if x 2 RN ; r > 0 then N (1) mN (BN (x; r)) = α(N)r : Proof. By known properties of the Lebesgue measure, (1) is equivalent to (2) mN (BN (0; 1)) = α(N) We proceed by induction on N. If N = 1, then p 2 π π1=2 m1(B1(0; 1)) = 2 = 1 = 1 = α(1) Γ( 2 ) Γ( 2 + 1) so (2) holds for N = 1. 1 2 HAUSDORFF MEASURES & APPLICATIONS Assume now N > 1 and (2) holds for all m < N. For any hyper- plane H through the origin, H \ BN (0; 1) = BN−1(0; 1). Hence by Fubini's Theorem, Z 1 p 2 mN (BN (0; 1)) = mN−1 BN−1(0; 1 − x ) dx −1 N−1 1 π 2 Z N−1 2 2 = N−1 (1 − x ) dx Γ( 2 + 1) −1 N−1 1 π 2 Z N−1 1 2 − 2 = N−1 u (1 − u) du Γ( 2 + 1) 0 N−1 π 2 N + 1 1 = · B ; N−1 2 2 Γ( 2 + 1) N−1 N+1 1 2 π Γ( 2 )Γ( 2 ) = N−1 · N Γ( 2 + 1) Γ( 2 + 1) N−1 p π 2 · π = N = α(N) Γ( 2 + 1) and (2) follows by induction. Recall, for A ⊆ RN , diam A := sup fkx − yk : x; y 2 Ag Then by Lemma 1.1 we have diam B (x; r)N m (B (x; r)) = α(N) N N N 2 We could then potentially define s-dimensional volume of a set A ⊆ RN by diam As vol A := α(s) s 2 This motivates the following definition. HAUSDORFF MEASURES & APPLICATIONS 3 Definition 1.2. For A ⊆ RN ; s ≥ 0; δ > 0; define ( 1 s ) X diam Cj [ Hs(A) := inf α(s) : A ⊆ C ; diam C ≤ δ δ 2 j j j=0 j2N The s-dimensional Hausdorff measure on RN is s s s H (A) := lim Hδ(A) = sup Hδ(A): δ!0 δ>0 From the definition we immediately get some simple properties, the proofs of which can be found in [1]: Proposition 1.3 (Properties of the Hausdorff Measure). Suppose s < t, A ⊆ RN . Then the following are true. (i) The Hausdorff measure is an outer measure on RN . (ii) H0 is the counting measure. (iii) If s > N then Hs(A) = 0. (iv) If Hs(A) < 1 then Ht(A) = 0. (v) If Ht(A) > 0 then Hs(A) = 0. N 2. H = mN N N The purpose of this section is to prove that H = mN on R . This is done in two steps: firstly, the Isodiametric Inequality is used to prove N H (A) ≤ mN (A), then a corollary to the Vitali Covering Lemma is N used to show mN (A) ≤ H (A). Lemma 2.1 (Brunn-Minkowski Inequality). Suppose t 2 [0; 1] and A; B ⊆ RN . Then 1=N 1=N 1=N mN (tA + (1 − t)B) ≥ tmN (A) + (1 − t)mN (B) A proof of the Brunn-Minkowski Inequality can be found in [2]. Theorem 2.2 (Isodiametric Inequality). If A ⊆ RN , then diam AN (3) m (A) ≤ α(N) N 2 4 HAUSDORFF MEASURES & APPLICATIONS Proof. (3) is obvious if diam A = 1, so assume diam A < 1. Set 1 1 0 0 B = 2 (A − A) = 2 (a − a ): a; a 2 A . The Brunn-Minkowski Inequality (Lemma 2.1) implies 1 1 N m (B) ≥ m (A)1=N + m (−A)1=N = m (A): N 2 N 2 N N 1 0 0 1 0 If x 2 B, then x = 2 (a−a ) for some a; a 2 A. So −x = 2 (a − a) 2 B, 1 diam B and hence kxk = 2 kx − (−x)k ≤ 2 for any x 2 B, so diam B B ⊆ BN (0; 2 ). Since by definition diam B ≤ diam A, we get diam B m (A) ≤ m (B) ≤ m B 0; N N N 2 diam B N diam AN = α(N) ≤ α(N) : 2 2 Corollary 2.3. For any A ⊆ RN , N mN (A) ≤ H (A): [ Proof. Fix δ > 0. Suppose A ⊆ Cj, diam Cj ≤ δ. Then j2N 1 1 N X X diam Cj m (A) ≤ m (C ) ≤ α(N) : N N j 2 j=0 j−0 N Taking infimum, we see mN (A) ≤ Hδ (A). The result follows by letting δ ! 0. Intuitively, the Isodiametric Inequality can be thought of as a con- sequence of "symmetrisation". If A ⊆ RN is any set and H is a hyper- plane through the origin such that H \ A 6= ;, then we may apply the Steiner symmetrisation of A with respect to H by shifting every per- pendicular vector to H in A so that it is symmetric about H. Then the diameter of the symmetrisation is no larger than that of the original set; moreover, Lebesgue measure is invariant under such transformations. Applying this to each coordinate axis fits a set with the same measure as A inside a ball with diameter no larger than A; this is exactly the Isodiametric Inequality. The reverse inequality unfortunately does not have an analogous in- tuition, but can be proved using a useful lemma. HAUSDORFF MEASURES & APPLICATIONS 5 Lemma 2.4. Fix δ > 0. If U ⊆ RN is any open set then there ex- ist a countable family of disjoint closed balls fBkgk2N in U such that diam Bk ≤ δ and ! [ mN (U) = mN Bk k2N We refer the reader to [1] for the proof of both Lemma 2.4 and the Vitali Covering Theorem on which it is based. We now are almost ready to prove the main result of this section. N Lemma 2.5. If mN (A) = 0, then H (A) = 0. Proof. Fix δ; > 0. From basic measure theoretic results (see [1]), [ we may suppose A ⊆ Qj, Qj dyadic cubes, with diam Qj ≤ δ, j2N 1 X 2N vol Q < . j N N=2 j=0 p N N Noting that (diam Qj) = ( N) vol Qj, we find 1 N X diam Qj HN (A) ≤ α(N) δ 2 j=0 1 −N N=2 X = 2 N vol Qj j=0 < . Letting , δ ! 0 concludes the proof. N Theorem 2.6. HN = mN on R . Proof. In light of Corollary 2.3 we need only show that HN (A) ≤ m (A) for all A ⊆ N . Fix δ > 0;A ⊆ N and suppose A ⊆ S R ; N R R j2N j Rj open rectangles. By Lemma 2.4, for each j 2 N there exist disjoint open balls fBj;kgk2N such that 6 HAUSDORFF MEASURES & APPLICATIONS [ Bj;k ⊆ Rj; and k2N 1 ! X [ mN (Bj;k) = mN Bj;k = mN (Rj): k=0 k2N ! [ Since mN Rj − Bj;k = 0, by Lemma 2.5 we have that k2 ! N ! N [ N [ N Hδ Rj − Bj;k = 0, that is, Hδ Bj;k = Hδ (Rj). k2N k2N Hence, by Lemma 1.1, 1 N X N Hδ (A) ≤ Hδ (Rj) j=0 1 1 N X X diam Bj;k ≤ α(N) 2 j=0 k=0 1 1 X X = mN (Bj;k) j=0 k=0 1 1 X X = mN (Rj) = vol Rj: j=0 j=0 Taking infimum and then letting δ ! 0 gives the result. 3. Rademacher's Theorem In this next section we investigate Rademacher's Theorem, which as- serts that Lipschitz functions are differentiable almost everywhere, that is, except on a set of measure zero. In particular, Lipschitz functions are sufficiently smooth to derive (and apply) results that generalise Fubini's Theorem, transformation formulae and more. Definition 3.1. Let f : RN ! RM be a function. We say f is Lipschitz if there exists K > 0 such that, for every x; y 2 RN , kf(x) − f(y)k ≤ Kkx − yk: We define the Lipschitz constant of f to be kf(x) − f(y)k Lip(f) := sup : x; y 2 N : kx − yk R HAUSDORFF MEASURES & APPLICATIONS 7 Definition 3.2. With f defined as above, we say f is differentiable at a 2 RN if there exists a linear map L : RN ! RM such that f(x) − f(a) − L(y − x) lim = 0: x!a kx − ak Since clearly such a map must be unique, we define Df(a) := L; the derivative of f at a. We first look at the special case where N = M = 1, in which case the derivative coincides with our normal notion of one dimensional derivative.

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