Chapter 3 Contractions

Chapter 3 Contractions

Chapter 3 Contractions In this chapter we discuss contractions which are of fundamental importance for the field of analysis, and essential tools for proving properties of ODEs. Before we discuss them, we first need to introduce some background on the setting of metric spaces. 3.1 Metric spaces Definition 3.1.1. Consider a set X, and a distance function d : X × X ! R satisfying 1. d(x; y) = d(y; x) (symmetric), 2. d(x; y) = 0 , x = y 3. d(x; y) + d(y; z) ≥ d(x; z) (triangle inequality) for all x; y; z 2 X. Then (X; d) is called a metric space. Note that it follows from the above prescribed conditions, that the distance function is positive definite: d(x; y) ≥ 0. We introduce a few elementary notions in metric spaces. We define the open r-ball at x 2 X as B(x; r) := fy 2 X j d(x; y) < rg: A set A ⊂ X is called bounded if it is contained in an r-ball for some r < 1, and open if for all x 2 A there exists an r such that B(x; r) ⊂ A. The interior of a set is the union of all its open subsets. Any open subset of X containing x is called a neighbourhood of x 2 X.A point x 2 X is a boundary point of a subset A ⊂ X if for all neighbourhoods U of x, we have U \ A 6= ; and U n A 6= ;. The boundary @A of A ⊂ X is the set of all boundary points of A. The closure of A, is defined as the set A¯ := fx 2 X j B(x; r) \ A 6= ;; 8r > 0g: A set A is closed is A = A¯, and A ⊂ X is dense in X if A¯ = X. A set A is nowhere dense if its closure has empty interior. 25 26 CHAPTER 3. CONTRACTIONS A point x 2 X is called an accumulation point of a set A ⊂ X if all all balls B(x; ") intersect Afxg. The set of accumulation points of A is called the derived set A0. A set A is closed if A0 ⊂ A and A¯ = A [ A0. A is called perfect if A = A0. We say that a sequence fxngn2N if 8" > 0 there exists N 2 N such that 8n ≥ N we have d(xn; x) < ". We say that two sequences fxngn2N and fyngn2N converge exponentially (or with n exponential speed) to each other if d(xn; yn) < cd for some c > 0 and 0 ≤ d < 1. The sequence is a Cauchy sequence if 8 " > 0 there exists N 2 N such that d(xi; xj) < " whenever i; j ≥ N. A metric space is called complete if every Cauchy sequence converges in it. Examples of complete metric spaces are Rn with the (usual) Euclidean metric, and all closed subsets of Rn with this metric. 3.2 The Contraction Mapping Theorem Definition 3.2.1 (Contraction). A map F : X ! X, where (X; d) is a metric space, is a contraction if there exists K < 1 such that d(F (x);F (y)) ≤ Kd(x; y); 8x; y 2 X: (3.2.1) A condition of the type (3.2.1) is called a Lipschitz condition, where K ≥ 0 is called the Lipschitz constant. Contractions are thus Lipschitz maps with a Lipschitz constant that is smaller than 1. We now formulate the central result about contractions. Theorem 3.2.2 (Contraction mapping theorem). Let X be a complete metric space, and F : X ! X be a contraction. Then F has a unique fixed point, and under the action of iterates of F : X ! X, all points converge with exponential speed to it. Proof. Iterating d(F (x);F (y)) ≤ Kd(x; y) gives d(F n(x);F n(y)) ≤ Knd(x; y); (3.2.2) n with x; y 2 X and n 2 N. Thus (F (x))n2N is a Cauchy sequence, because with m > n we have m−n−1 m−n−1 X X Kn d(F m(x);F n(x)) ≤ d(F n+k+1(x);F n+k(x)) ≤ Kn+kd(F (x); (x)) ≤ d(F (x); x) 1 − K k=0 k=0 and Kn ! 0 as n ! 1. In the last step we used the fact that with 0 ≤ K < 1 it follows that m−n−1 1 X X 1 Kk ≤ Kk = : 1 − K k=0 k=0 n Thus the limit limn!1 F (x) exists because Cauchy sequences converge in X. We denote the limit x0. By (3.2.2) under iteration by F all points in X converge to the same point as n n limn!1 d(F (x);F (y)) = 0 for all x; y 2 X so that if x converges to x0 then so does any y 2 X. 3.3. THE DERIVATIVE TEST 27 It remains to be shown that x0 is a fixed pont of F : F (x0) = x0. Using the triangle inequality we have n n n+1 n+1 d(x0;F (x0)) ≤ d(x0;F (x)) + d(F (x);F (x)) + d(F (x);F (x0)) n n ≤ (1 + K)d(x0;F (x)) + K d(x; F (x)); for all x 2 X and n 2 N. The right-hand-side of this inequality tends to zero as n ! 1, and hence F (x0) = x0. 3.3 The derivative test We show that in the case of a differentiable map F : X ! X, one can use the derivative to prove that it is a contraction (on some bounded closed subset of the phase space). We first consider the situation that F : I ! I, where I ⊂ R is a closed bounded interval. Proposition 3.3.1. Let I ⊂ R is a closed bounded interval, and F : I ! I a continuously differentiable (C1) function with jF 0(x)j < 1 for all x 2 I. Then F is a contraction. Proof. First we show that if F 0(x) ≤ K then F is Lipschitz with Lipschitz constant K. By the Mean Value Theorem, for any two points x; y 2 I there exists a c between x and y such that d(F (x);F (y)) = jF (x) − F (y)j = jF 0(c)(x − y)j = jF 0(c)jd(x; y) ≤ Kd(x; y): 0 At some point x0 2 I the maximum of jF (x)j will be attained since F is continuous, and 0 jF (x0)j < 1. Remark 3.3.2. The conclusion of Proposition 3.3.1 do not necessarily apply if the domain of F is taken to be the entire real line. Example 3.3.3 (Fibonacci's rabits). Leonardo Pisano, better known as Fibonacci, tried to understand how many pairs of rabits can be grown from one pair in one year. He figured out that each pair breads a pair every month, but a newborn pair only breads in the second month after birth. Let bn denote the number of rabit pairs at time n. Let b0 = 1 and in the firts month they bread one pair so b1 = 2. At time n = 2, again one pair is bread (from the one that were around at time n = 1, the other one does not yet have the required age to bread). Hence, b2 = b1 + b0. Subsequently, bn+1 = bn + bn−1. Expecting the growth to be exponential we would n like to see how fast these number grow, by calculating an = bn+1=bn. Namely, if bn ! cd as n ! 1 for some c; d then bn+1=bn ! d. We have 1 an+1 = bn+2=bn+1 = + 1: an 0 −2 Thus fangn2N is the orbit of a0 = 1 of the map g(x) = 1=x + 1. We have g (x) = −x . Thus g is not a contraction on (0; 1). But we note that a1 = 2 and consider the map g on the closed interval [3=2; 2]. We have g(3=2) = 5=3 > 3=2 and g(2) = 3=2. Hence g([3=2; 2]) ⊂ [3=2; 2]. 28 CHAPTER 3. CONTRACTIONS Furthermore, fro x 2 [3=2; 2] we have jg0(x)j = 1=x2 ≤ 4=9 < 1 so that g is a contraction on [3=2; 2]. Hence, by the contraction mapping theorem, there exists a unique fixed point, so 2 limn!1 an exists. The solution is a fixedp point of g(x), yielding x − x − 1 = 0. The only positive root of this equation is x = (1 + 5)=2. Example 3.3.4 (Newton's method). Finding the roots (preimages of zero) of a function F : R ! R is difficult in general. Newton's method is an approach to find such roots through iteration. The idea is rather straight forward. Suppose x0 is a guess for a root. We would like to improve our guess by chosing an improved approximation x1. We write the first order Taylor 0 expansion of F at x1 in terms of our knowledge about F at x0: F (x1) = F (x0)+F (x0)(x1 −x0). By setting F (x1) = 0 (our aim), we obtain from the Taylor expansion that 0 x1 = x0 − F (x0)=F (x0) =: G(x0): (3.3.1) We note that a fixed point y of G corresponds to a root of F if F 0(y) 6= 0. We call a fixed point y of a differentiable map G superattracting if G0(y) = 0. We have Proposition 3.3.5.

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