
Quotient Modules and Module Homomorphsims Kevin James Kevin James Quotient Modules and Module Homomorphsims Note For an R-module homomorphism φ : M ! N, ker(φ) is a submodule of M and φ(M) is a submodule of N. Definition Let R be a ring and let M; N be R-modules. 1 A map φ : M ! N is an R-module homomorphism provided 1 φ(x + y) = φ(x) + φ(y), 8x; y; 2 M, and 2 φ(rx) = rφ(x), 8r 2 R; x 2 M. 2 An R-module isomorphism is an R-module homomorphism which is also bijective. 3 Suppose φ : M ! N is an R-module homomorphism. ker(φ) = fm 2 M j φ(m) = 0N g. φ(M) = fφ(m) j m 2 Mg. 4 HomR (M; N) = fφ : M ! N j φ is an R-module homomorphismg. Kevin James Quotient Modules and Module Homomorphsims Definition Let R be a ring and let M; N be R-modules. 1 A map φ : M ! N is an R-module homomorphism provided 1 φ(x + y) = φ(x) + φ(y), 8x; y; 2 M, and 2 φ(rx) = rφ(x), 8r 2 R; x 2 M. 2 An R-module isomorphism is an R-module homomorphism which is also bijective. 3 Suppose φ : M ! N is an R-module homomorphism. ker(φ) = fm 2 M j φ(m) = 0N g. φ(M) = fφ(m) j m 2 Mg. 4 HomR (M; N) = fφ : M ! N j φ is an R-module homomorphismg. Note For an R-module homomorphism φ : M ! N, ker(φ) is a submodule of M and φ(M) is a submodule of N. Kevin James Quotient Modules and Module Homomorphsims 2 HomR (M; N) is and Abelian group under point-wise addition of functions. 3 If R is a commutative ring, then HomR (M; N) is an R-module with multiplication (rφ)(m) = rφ(m): 4 If φ 2 HomR (L; M) and 2 HomR (M; N), then ◦ φ 2 HomR (L; N). 5 HomR (M; M) is a ring with 1. When R is commutative, HomR (M; M) is an R-Algebra. Proposition Suppose that M; N are R-modules 1 φ : M ! N is an R-module homomorphism if and only if φ(rx + xy) = rφ(x) + sφ(y), 8r; s 2 R; x; y 2 M. Kevin James Quotient Modules and Module Homomorphsims 3 If R is a commutative ring, then HomR (M; N) is an R-module with multiplication (rφ)(m) = rφ(m): 4 If φ 2 HomR (L; M) and 2 HomR (M; N), then ◦ φ 2 HomR (L; N). 5 HomR (M; M) is a ring with 1. When R is commutative, HomR (M; M) is an R-Algebra. Proposition Suppose that M; N are R-modules 1 φ : M ! N is an R-module homomorphism if and only if φ(rx + xy) = rφ(x) + sφ(y), 8r; s 2 R; x; y 2 M. 2 HomR (M; N) is and Abelian group under point-wise addition of functions. Kevin James Quotient Modules and Module Homomorphsims 4 If φ 2 HomR (L; M) and 2 HomR (M; N), then ◦ φ 2 HomR (L; N). 5 HomR (M; M) is a ring with 1. When R is commutative, HomR (M; M) is an R-Algebra. Proposition Suppose that M; N are R-modules 1 φ : M ! N is an R-module homomorphism if and only if φ(rx + xy) = rφ(x) + sφ(y), 8r; s 2 R; x; y 2 M. 2 HomR (M; N) is and Abelian group under point-wise addition of functions. 3 If R is a commutative ring, then HomR (M; N) is an R-module with multiplication (rφ)(m) = rφ(m): Kevin James Quotient Modules and Module Homomorphsims 5 HomR (M; M) is a ring with 1. When R is commutative, HomR (M; M) is an R-Algebra. Proposition Suppose that M; N are R-modules 1 φ : M ! N is an R-module homomorphism if and only if φ(rx + xy) = rφ(x) + sφ(y), 8r; s 2 R; x; y 2 M. 2 HomR (M; N) is and Abelian group under point-wise addition of functions. 3 If R is a commutative ring, then HomR (M; N) is an R-module with multiplication (rφ)(m) = rφ(m): 4 If φ 2 HomR (L; M) and 2 HomR (M; N), then ◦ φ 2 HomR (L; N). Kevin James Quotient Modules and Module Homomorphsims Proposition Suppose that M; N are R-modules 1 φ : M ! N is an R-module homomorphism if and only if φ(rx + xy) = rφ(x) + sφ(y), 8r; s 2 R; x; y 2 M. 2 HomR (M; N) is and Abelian group under point-wise addition of functions. 3 If R is a commutative ring, then HomR (M; N) is an R-module with multiplication (rφ)(m) = rφ(m): 4 If φ 2 HomR (L; M) and 2 HomR (M; N), then ◦ φ 2 HomR (L; N). 5 HomR (M; M) is a ring with 1. When R is commutative, HomR (M; M) is an R-Algebra. Kevin James Quotient Modules and Module Homomorphsims Note 1 If R is commutative, then we can define ι : R ! EndR (M) by ι(r) = r · IdM . 2 ι(R) ⊆ Center(End M). 3 If 1R 2 R, then EndR (M) is an R-Algebra. 4 If R is a field then ι is injective and ι(R) is called the subring of scalar maps. Definition HomR (M; N) is called the endomorphism ring of M and is typically denoted EndR (M) or simply End M. Kevin James Quotient Modules and Module Homomorphsims Definition HomR (M; N) is called the endomorphism ring of M and is typically denoted EndR (M) or simply End M. Note 1 If R is commutative, then we can define ι : R ! EndR (M) by ι(r) = r · IdM . 2 ι(R) ⊆ Center(End M). 3 If 1R 2 R, then EndR (M) is an R-Algebra. 4 If R is a field then ι is injective and ι(R) is called the subring of scalar maps. Kevin James Quotient Modules and Module Homomorphsims Definition Let A; B be R-submodules of and R-module M. Then we define A + B = fa + b j a 2 A; b 2 Bg: Fact A + B is the smallest R-submodule of M containing both A and B. Proposition Let R be a ring and let M be an R-module and N ≤ M. The group M=N can be given an R-module structure by defining r(x + N) = rx + N; 8r 2 R;(x + N) 2 M=N: The projection map π : M ! N is a surjective R-module homomorphism. Kevin James Quotient Modules and Module Homomorphsims Fact A + B is the smallest R-submodule of M containing both A and B. Proposition Let R be a ring and let M be an R-module and N ≤ M. The group M=N can be given an R-module structure by defining r(x + N) = rx + N; 8r 2 R;(x + N) 2 M=N: The projection map π : M ! N is a surjective R-module homomorphism. Definition Let A; B be R-submodules of and R-module M. Then we define A + B = fa + b j a 2 A; b 2 Bg: Kevin James Quotient Modules and Module Homomorphsims Proposition Let R be a ring and let M be an R-module and N ≤ M. The group M=N can be given an R-module structure by defining r(x + N) = rx + N; 8r 2 R;(x + N) 2 M=N: The projection map π : M ! N is a surjective R-module homomorphism. Definition Let A; B be R-submodules of and R-module M. Then we define A + B = fa + b j a 2 A; b 2 Bg: Fact A + B is the smallest R-submodule of M containing both A and B. Kevin James Quotient Modules and Module Homomorphsims Theorem (Isomorphism Theorems) 1 Suppose that φ : M ! N 2 HomR (M; N). Then, ker(φ) ≤ M and M= ker(φ) =∼ φ(M). 2 Suppose that A; B ≤ M. Then, (A + B)=B =∼ A=(A \ B): 3 Suppose that A; B ≤ M and A ⊆ B. Then, M=A =∼ M=B: M=B 4 Suppose that N ≤ M. Then, fN ≤ K ≤ Mg 1−!f−1 L ≤ M=Ng under the map K 7! K=N. This correspondence commutes with sums and intersections. Kevin James Quotient Modules and Module Homomorphsims.
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