Mathematical Analysis I Exercise Sheet 6

Mathematical Analysis I Exercise Sheet 6

Mathematical Analysis I Exercise sheet 6 12 November 2015 References: Abbott 2.7. Bartle & Sherbert 3.7 P1 1. Define what it means for an infinite series n=1 an to converge. P1 (i) Prove that if n=1 an converges then (an) ! 0. (ii) Give a counterexample to the converse of (i). P1 n n (iii) Let r 2 R. Prove that the series n=1 r converges if and only if (r ) ! 0, and write down its limit in this case. 2. P1 (i) Let (an) be a sequence of nonnegative reals. Prove that the series n=1 an is convergent if and only if the sequence of its partial sums (a1 + ··· + an) is bounded. P1 1 (ii) Using the result of (i), prove that the harmonic series n=1 n is divergent. P1 1 (iii) Deduce from (ii) that n=1 np diverges when 0 < p ≤ 1. P1 1 (iv) Prove that n=1 np converges when p > 1. [If you use the Cauchy Condensation Test here you must prove it, so you may wish to argue directly instead.] 3. Let (an) be a sequence of reals that is monotone decreasing and converges to 0. P1 n+1 (i) Prove that the alternating series n=1(−1) an converges to a limit between a1 − a2 and a1. [Two methods of proving this are (1) to use the Cauchy Criterion for series, or (2) to apply the Monotone Convergence Theorem to the two sequences of partial sums (a1 − a2 + · · · − a2n) and (a1 − a2 + · · · − a2n + a2n+1).] P1 (−1)n+1 (ii) Deduce from (i) that the alternating series n=1 np converges for p > 0. [In particular the P1 (−1)n+1 1 alternating harmonic series n=1 n converges to a limit between 2 and 1 (the limit, as you will later prove, is ln 2).] 4. For each of the following series, prove either that it diverges, or that it converges to a limit and in this case determine the limit: P1 n (i) n=1 2n P1 1 (ii) n=1 n(n+1) P1 p1 (iii) n=1 n n n P1 n+1 2n+1 (iv) n=1(−1) n(n+1) (−1)n (v) P1 p n=1 n+1 1 P1 5. Let (an) be a sequence of strictly positive reals and suppose that n=1 an is convergent. Either prove or give a counterxample to the following statements: P1 2 (i) the series n=1 an converges, P1 p (ii) the series n=1 an converges, P1 a1+a2+···+an (iv) the series n=1 n diverges. P1 6. Define what is meant by a rearrangement of a series n=1 an. P1 P1 (i) Prove that if n=1 janj converges then so does n=1 an. P1 P1 (ii) Prove further that if n=1 janj converges then any rearrangement of the series n=1 an converges to the same limit. P1 P1 (iii) Prove that if n=1 an converges but n=1 janj diverges then, for any l 2 R, there is some P1 rearrangement of n=1 an that converges to l. [This result is part of what is known as Riemann's Series Theorem. For simplicity you may assume an 6= 0 for each n 2 N (this does not affect the result in the end, but helps define the + − construction needed in the proof more smoothly). Define an = maxf0; ang and an = minf0; ang. P1 P1 + P1 − Since n=1 janj diverges, the series n=1 an diverges to +1 and the series n=1 an diverges P1 to −∞. Use partial sums of these two series to construct a rearrangement of n=1 an that is convergent to l.] 2.

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