N (North) Equator Latitude and Declination

N (North) Equator Latitude and Declination

Latitude and Declination First, some definitions. The observer’s zenith is the point directly over the observer’s head. The observer’s meridian is an imaginary arc in the sky which runs north-south (so passes over the poles) and through the Light from observer’s zenith. The meridian lies directly over the observer’s great circle North Star N (North) of longitude. The observer’s horizon is the plane tangent to the earth and Star passing through the observer; it’s perpendicular to the line from the center of the earth, passing through the observer, and going out toward the zenith. Horizon Line The celestial equator is the plane which passes through the earth’s equa- tor and extends out into space. The observed altitude of a star is its angular distance above the observer’s horizon. A star’s altitude will vary with the time of observation. A star’s declination is its angular distance above the celestial equator. The decli- nation is also 90 degrees minus the angle the star makes with the earth’s axis; Since the North Star (Polaris) lies on this axis, we can say that the declination is the complement of the star’s angular distance from the North Star (Polaris). We are assuming that the observer, the zenith, the star observed, and Polaris all lie in the same plane. This will happen when the star “crosses the meridian” of the observer. (Note: when the sun crosses the meridian of the observer, it’s noon:thus,AM=Ante (before) Meridian and PM = B Post Meridian!) A D Zenith Angle A is the altitude of Polaris; it’s also equal to the observer’s latitude L. To see this, note that A is the complement of B + D.ButB + D equals C since they are “vertical angles.” But L is the complement of C since they lie in a right triangle. Thus, Latitude = L = A. Observer Next, note that A + B = the Altitude of the star, by the above definition of altitude. But B is the angular distance of the star from Polaris, so B = C (90 — Declination). Thus, we have: Altitude = A + B = Latitude + (90 — Declination). We can solve this for the Latitude, giving us the fundamental formula: Latitude = Altitude + Declination 90 − L = Latitude This formula works for any star. If the star lies south of the equator Equator (so its angular distance from Polaris is greater than 90 degrees), we must take the declination to be negative. We must also take latitudes below the equator to be negative..

View Full Text

Details

  • File Type
    pdf
  • Upload Time
    -
  • Content Languages
    English
  • Upload User
    Anonymous/Not logged-in
  • File Pages
    1 Page
  • File Size
    -

Download

Channel Download Status
Express Download Enable

Copyright

We respect the copyrights and intellectual property rights of all users. All uploaded documents are either original works of the uploader or authorized works of the rightful owners.

  • Not to be reproduced or distributed without explicit permission.
  • Not used for commercial purposes outside of approved use cases.
  • Not used to infringe on the rights of the original creators.
  • If you believe any content infringes your copyright, please contact us immediately.

Support

For help with questions, suggestions, or problems, please contact us