NEW ZEALAND JOURNAL OF Volume 29 (2000), 73-90

FINE TOPOLOGY AND GROWTH OF SMALL SUBHARMONIC AND 5-SUBHARMONIC FUNCTIONS IN THE COMPLEX PLANE

A. Yu. S h a h v e r d i a n , M. E s s e n a n d G.S. H o v a n e s s i a n (Received February 1999)

Abstract. The paper gives asymptotical estimates of the behaviour at infinity of small subharmonic or <5-subharmonic functions: this behaviour depends on different kinds of deficiencies. The exceptional sets are described in capacity terms. Our growth restrictions are expressed in integral weight form. W e use a generalization of the notion of thin set from which depends on the corresponding weight .

1. Introduction The paper considers the asymptotical behavior of the quantities

“ <*) and (1) T( 1* 1) B(\x\) where w is the difference of two functions subharmonic in the complex plane C = {|x| < oo}, u is subharmonic in C, T(r) is Nevanlinna’s characteristic function of w , and B(r) = max0<^<27r u(rel

1991 AMS Mathematics Subject Classification: 31A05, 31A15. 74 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN which characterize the growth of the functions w and u. Our exceptional sets are characterized by generalized Wiener conditions involving the function u.

2. Some Definitions

We shall work with a modified logarithmic capacity 7 (e ), defined for subsets e of Co = C \ {0}. Its properties are described in the appendix. Assuming that the infimum below is positive, we define the capacity 7 (e) of a compact set e contained in Co = C\{0} in the following way:

7 (e) = (inf Je Je ln • (2 )

Here the infimum is taken over all Borel measures /1 with /i(e ) = 1 and supp(//) C e. We define 7 (e) first for compact sets and extend it then in the usual way to arbitrary sets. For more details on the definition, we refer to the appendix. We suppose always that w — u — v where u and v are subharmonic in C, fi is the Riesz measure of u, v is the Riesz measure of v and T is the Nevanlinna characteristic function, defined by (cf. e.g. pp. 127 and 508 in [13]) 1 r2n ^ (r) ~ W ~ max{0, w(rel^)}d(j) + N (r,v) Jo where N(r, v) _ f nv(£) ^ n„(t) = v(\x\ < t). Ji t We define

6(w) = 1 - lim sup , A (w) = 1 - lim inf ^ ^ . (3) r—00 J- (r) r—00 T(r) In the case when w = ln|/| and / is a meromorphic function in C, the quantities S(w) and A(u>) coincide with the Nevanlinna deficiency 6f (00) at 00 (cf. e.g. p. 709 in [13]) and the Valiron deficiency A /(0 ) at 0, respectively. For u subharmonic, we introduce d(u) = 1 — lim inf ^ 0 < d(u) < 1. r—> 00 B(r) Let cu be a positive monotone (increasing or decreasing) function defined in the interval (1,00) and let a) — m in{l, a}. If q > 1 is a given number, we consider sets e C Co for which the condition OO ^2uj(qn)7 f (en) < 00 (4) 71=1 holds. Here en = ef) {qn < |x| < qn+1}. Using terminology from [4] we call such sets w-thin. It follows from a criterion of Euler that the condition SMALL SUBHARMONIC AND .5-SUBHARMONIC FUNCTIONS 75

Hence if (5) is not true, the relation (4) holds for all sets e. In particular, it is even possible that e = Co (and the statements of Theorems 1 and 2 lose their significance). If (5) holds, then it follows from (4) that e is a small set in an infinite number of rings qn < |x| < qn+1: lim inf7 (en) = 0, 71— ► OO while for each natural n we have 7 ^({x : qn < |x| < increases, then the symbol “f” in (4) can be erased; consequently, for each such w-thin set e we have

OO ^ 7 (en) < oo. (6) 71=1 We note that when 7 (en) is small, en must be a small subset of the annulus {qn < |a:| < qn+1} (cf. the appendix for details). The 7-capacity of the annu­ lus is infinite. Everywhere below, we suppose that the function u satisfies the doubling condi­ tion

uj(2r)/uj(r) = 0(1) (r —* 00) (7)

in the case when uj is increasing. When uj is decreasing, we assume instead that

uj(r)/u(2r) = 0(1) (r —► 00). (7a)

3. Main Results Let us now formulate our main results which include Theorems 1, 2, 4 and Corollaries 9-11. In a certain sense, they generalize or supplement some known results mentioned above. It should be noticed that the major limitations on the growth of (8-) subharmonic functions are given below in integral weight form. We have not been able to obtain any non-trivial results for functions of positive order. Our theorems are of interest in the study of functions of order zero. Some lower estimates of (<5-) subharmonic functions using capacity, can be found in [18]—[21].

T heorem 1 . Let w be a S-subharmonic function and assume that for some mono­ tone function u the condition

[ Y fM ) K (8) J\x\

holds. Then for an arbitrary number 9 in (0,1), there exists a w-thin set e = e# such that

limint (9) X - + 0 0 , x & e 1

Theorem 2. Let u be a subharmonic function and assume that for some monotone function uj the condition

[ < ( 1 0 ) ./|x|

liminf > 1 — 9 ~ 1d(u). (11) x-*oo,x?e B(\x\) ~ v J K ’

Remark 3. If 5(w) > A(w), the right hand member in (9) will be positive for 6 close to 1. Similarly, the right hand number in (11) will be positive for 6 close to 1 if d(u) < 1.

Theorem 4. Let u be a subharmonic function such that B(r) — N (r) + 0(1) (r —► oo) and assume that for some monotone oo the condition

uj(\x\)dfi(x) < oo (12) I,|a:] oo, x e). (13) Remark 5. It follows from proof of Theorem 4, that if a subharmonic function satisfies the condition B = N + o(l), then for a given positive number e the excep­ tional set e in (13) can be constructed in such a way that the absolute value of the bounded quantity 0(1) in (13) does not exceed e for all x which are not in e.

It is not difficult to prove the following statement, which gives conditions on w (or u) when (8) (or (10)) is true (the proof will be given in Section 4).

Lemma 6. Suppose that for a 5-subharmonic w (or subharmonic u) and some function k > 1, we have T(rcf)(r)) = 0(T(r)) (or B(r(j>(r)) — 0 (B (r ))) . (14)

If uj is decreasing and

r — dr < oo (15) Ji In 4>{r) r then (8) (or (10)) holds. If uj is increasing, (15) holds and a;(r) = O (ln 0 (r)), r —► oo, (16) then (8) or (10) holds.

If uj is increasing and

r n f t u M / r « 4 ) dr< \ (17) Ji In r r \ Ji ln3r r J' then (8) (or (10)) holds.

A function (f>(r) satisfying (14) can be defined in the following way. If w is a given (5-subharmonic function and C is a given (big) constant, we define 0(r) = sup{t > 1 : T(rt) < CT(r)}. If T(r) ~ (lnr)Q for some a > 1, we can choose (r) ~ r (or 0(r) ~ r7 for some positive 7 ). If T(r) grows in a less regular way, other choices of 4> may be useful. A similar remark holds for subharmonic functions and B(r). SMALL SUBHARMONIC AND 5-SUBHARMONIC FUNCTIONS 77

Remark 7. To describe the results of Kubota [14] mentioned in the introduction, we consider a measurable subset e of ( 0, oo) and the lower density lim in f^ oo |e fl (0,r)|/r, (where | • | denotes Lebesgue measure). If / is a meromorphic function of order 0 and 8(oc, f ) and A (oo, / ) denote the Nevanlinna and Valiron deficiencies of / at infinity (cf. (3)), then Kubota proves that if <5(oo, / ) is positive, then

oo,r^e r_,00jrge where e is a set of lower density 0, T(r, f) is the Nevanlinna characteristic and B (r, / ) and //(r, / ) denote the maximum and the minimum modulus of / . The exceptional set is here a union of annuli in the plane and considerably larger than the exceptional sets in Theorems 1, 2 and 4 which are defined in terms of capacity and which depend on a parameter 9.

Remark 8. To discuss the relation between our results and the work of W. Hayman [1 1 ], we say that a set e is a C-set if it can be covered by discs CXn)T.n with centers x n and radii rn satisfying the condition J2<^L irn/\xn\ < oo. In [11], Hayman proved that if

B(r) = 0(ln 2r), (18) then there exists a C-set e such that for x —> oo, x £ e, we have

u{x) = £(|x|) + o(B(|a;|). Furthermore, if

B (r) = O(lnr) ^and then J d^i < oo^ , (19) then there exists a C-set e such that for x —> oo, x & e, we have

u{x) — J3(|a;|) + o(l). It follows from a result of G. Piranian [17] that in Hayman’s theorem the assumption (18) cannot be replaced by the condition B — where limr_^oo tp (r)/In2 r = oo. It can be proved (see [18], [19]) that a 1-thin set is a C-set and that there exist C-sets that are not 1-thin. The set n 0

If 9 is a given number in the interval (0,1), let us consider the set e = {x G C : u(x) < 9B(\x\)}. If (19) holds, Arsove and Huber [2] have proved that a Wiener condition (see [4]) holds for e at oo (cf. also Theorem 4 in Essen, Hayman and Huber [8]). In other words, e is thin at infinity which means that

OO ^ r i 7 (en) < oo (20) n = l (cf. (6.2) in Essen and Jackson [9]). Essen gave in [7] further results on this problem in the case B = 0(ip) where ip is a slowly oscillating function which is 78 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN

such that lim sup^oo ^ (r j/ln 2 r = oo. For a result concerning entire functions with slowly oscillating Nevanlinna characteristic, see [21]. As examples of applications of Lemma 6, we consider functions w or u of order zero. If (14) holds with (j){r) = r, we can choose cj(r) = (lnr)7 for some 7 G [0,1) in (15). Applying Theorem 1 or 2 in the case 7 = 0, we conclude that there exists a 1-thin exceptional set e such that (9) or (11) holds. We note that formally, formula (4) with u> constant coincides with a condition for minimal thinness in a Stolz domain in a half-plane given by H. Jackson (cf. (1.3) in [9]). Note also, that such sets arise in lower estimates of (5-) subharmonic functions (see [20]). If the behavior of w or u is such that we can only say that (14) holds with 0(r) = lnr, we can choose u>(r) = (lnr)-1 in (15). Thus a more irregular behavior of w or u will give us a larger exceptional set. Conditions (15) and (16) can be applied to functions for which T(r) or B(r) grow as (lnr)a for some a > 1. Condition (17) works only if 1 < a < 2. For functions which grow very slowly, we have the following corollaries of Theo­ rems 1, 2, 4 and Lemma 6 (proofs will be given in Section 4). In Corollary 11 we consider the special case of a logarithmic potential in the plane C,

u(x) = Uft(x) = / In \x — C|

Corollary 9. If u is subharmonic and we have the relation B(r) = 0(lnar)(r —* 00) where 1 < a < 2 , then for arbitrary f3 in (0,2 — a), there exists a set e in the complex plane C such that for x —* 00, x # e,

OO n^'y(en) < 00 and u(x) = #(|a;|) + o(J5(|x|)). ( 21) 71=1 Corollary 10. If u is subharmonic and the relation (19) holds, then for each function uj satisfying the condition

/ wd[L < 00 (22) J € there exist sets e ^ and e ^ such that for x —► oo; x ^ OO ^ nuj(qn)^ ( e ^ ) < 00 and u(x) = 5(|x|) + o(i?(|a;|) (23) 71=1

and for x —> 00, x £ e ^ OO ' y ^ o;(g n)7 (e ^ ) < 00 and u(x) = B(|x|) + 0(1). (24) 71=1

Corollary 11. If u (= uM) is a logarithmic potential and ufJ,( 0) 7^ 00 (which im­ plies that f ln+ |C|(2/z(C) < °°)> then there exist sets e ^ and e ^ such that for x —► 00, x OO ^ n27 (e ^ ) < 00 and u(x) = n^{\x\) In |x| + o(nM(|x|) In |x|), (25) 71=1 SMALL SUBHARMONIC AND 5-SUBHARMONIC FUNCTIONS 79 and e ^ is thin at infinity ( cf. (20)) and for x —> oo, x 0 u(x) = nM(|x|)ln |x| + 0 (1). (26) From Remark 5 and the proofs of the corollaries, we see that if £ is a given positive number, we can choose the exceptional sets in Corollaries 10 and 11 in such a way that the absolute values of 0(l)-term s in (24) and (26) do not exceed e. In other words, if we consider the collection of sets (compare the notion of fine topology defined in [4]), = {C\e : e is w-thin} then (24) can be rewritten in the more convenient form: u(x) = £?(|x|) + e(x) where 7^ — lim e(x) — 0 x — ►OO and uj satisfies (22); such notation can be also used for (26): u(x) = nJ\x\) In Ixl + e(x) where %j — lim e(x) — 0 x — ►OO and uj = lnr. All the statements of Theorems 1, 2, 4 and Corollaries 9-11 can be reformulated in these fine topological terms or, as in [20] and [21], in terms of convergence on filters. For instance, we can write relation (9) from Theorem 1 in the form Tu - lim inf > 8 - A . x->oo 1 (Jx|) After applying the transformation x —> (x — £)-1 (£ ^ oo), the condition (20) mentioned in Corollary 11 coincides with the Wiener criterion for irregularity of a point £ in the . This statement is in fact an analogy for case of a logarithmic potential (for case of Riesz potentials see [20]) of a theorem of H. Cartan [6] (see also [4], [15], [20]) on the continuity of a Newton potential in the classical fine topology.

4. Proofs of Results Let us first introduce some notions and definitions which will be used in proofs. Everywhere below r ( x - £ ) D r = (|x| < r), [x,£]r = D x,r = {£ : [z,£] < r] r2 — :r£ (£>! = £>, M U = [*.■£])• We will consider the Green potential of a Borel measure fi > 0 defined in D r

ufX{x,r)= [ In 1-r d/i(0 , u»{x, 1) = wM(x). JDr 1*^5 Sjr The Green capacity C9r of compact subsets e C D r is defined by

C9r{e) = (^ini , (Cg i = C g), (27) where the infimum is taken over all Borel measures /i for which fi(e) = 1 and supp(fi) C e. If w+ = max(w, 0), w+ = (—w)+ , w = u — v and -j />2it i /*2ir m + (w,r) = — / w+ (rel)d(f), m +(w ,r) = — / w+ (rel^)d(f) 2tt Jo 2tt Jo 80 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN then it follows from Nevanlinna’s theorem

Tw(r) — m+ (w,r) + N(r,v ) — m +(w ,r) + N (r ,u ) + u>(0) that for the quantities (3) we have

st \ 1- • r m + (w,r) . . . m + (w ,r) S(W) = hm , A(W) = lun sup .

In the Proof of Lemma 14, we will need two remarks. We note that the “triangle inequality” for the pseudohyperbolic distance [x, £] follows from M i M < , ,, < [», »] + [*. a m \ l-[*,*][*,€] l+ [*,*][*,{] which holds if the moduli of x, z, £ are all either smaller than 1 or larger than 1 (cf. formula 1.(10) in [10]).

Remark 12. If 0 ^ s ^ A ^ 1 and oc and ^ BiFG in , it follows from that if [x, £] < s and [f, t] < [A, s] then [x, t] < A. Thus,

U Dt,[x,s] C Dx,\. (29) t£DXiS

Remark 13 (see also [21]). If /i is a unit measure in D and A is an arbitrary number in ( 0, oo) then

Cg({x G D : u»(x) > A}) < i (30) A Proof of Remark 13. Since u^ is a lower semicontinuous function, G = {x : u^(x) > A} is an . Let e C G be a compact set (we can assume Cg(e) > 0), and let v be a minimizing measure associated with e ([13]). By Fubini’s theorem, we know that J u^du = J uvdp,.

The left-hand integral is greater than A because e C G. According to Frostman’s theorem (cf. p. 60 in [22] or Theorem 5.8 in [13]), we have u"(x) < (Cg(e))~1 for every x € D. Therefore the right-hand integral is less than (Cg(e)) . Remark 13 is proved.

Lemma 14. Let 0 < r < oo, let n be a finite Borel measure in D r and let for t > 0 e = {x G D r : «M(x,r) > r }. Then for each p > r (cosh(r/3)) 1 and pT = r[p/r, 2 ( cosh(r/3)) 1)] the inequality

C 9r ffy - M < ^ - k i T ) ^ { P r < 1*1 < r}) (31) holds, where 0 < k(r) = 0 (r_1)(r —> +oo).

Proof of Lemma 14. It is enough to prove Lemma for the case r = 1 - the general statement can be obtained via the transformation x —» rx, x G D. It is also clear that we can assume p,(D) = 1. It is easy to see that for arbitrary u with v{D ) < 1, 0 < 7] < 1, and every x 0 UtesuD ttT] (here Sv = supp(z/)) SMALL SUBHARMONIC AND 5-SUBHARMONIC FUNCTIONS 81

- indeed, for such x and every £ G 5„, g(x, £) = ln l/[x,£] < c{rf). If r is given, we define numbers 0

a = 6XP (“D ,6XP (~D ’ ^ expH )- (33) It is not difficult to check that c([a,(3]) < r/2 . The system of discs {-Dx,a}|x|

Indeed, if x G D is contained in p > 1 discs D^itp G a\, then for each E D X)p. Let ao = (a + /?)/(1 + a/3). According to (29) with [A, s] = [ao> P\ — we have for every i •^Cii/3 Dx,c*o' Consequently the sum of the non-Euclidean surface measures of the discs C does not exceed 6s, where

s — 47a r- ao 1 - a 2 is the non-Euclidean surface measure of D Xjao. It follows that

pa2/ ( I - a 2) < 6a § / ( l - a § ) which immediately gives (34). From (33) it is easy to see that

ko{r) = 0(1) (r -»■ +oo). (35)

Let be the restriction of ^ to the disc D Xnjp and let un be the restriction of /i to the complement D%n p- We define = e ^ D Ac„,a- If x G and y D Xnyp, then by (28) [x,y\ > [a,/?]. Applying (32) with rj = [a,/3], it follows that

uVn [x] < c([a,(3]) < r/2, x G e £ \ (36)

Since u^n = , it follows from (36) and the definition of that

ufXn(x ) > T / 2, x G

Hence e^ c{xG Ac„,a '■ ufJ,n(x) > r /4 } which by (30) implies that

Cg(eiT)) <

Let M n = max{|rr| : x G D Xnip}. If p G (0,1) is arbitrary, then

c g ( e « f > < 1*1 < 1)) < E C & P ) ^ 7 E Mn>p Mn>p

< - « l u ,/>I = I U I (37> Mn>p J \Mn>p 82 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN where k(r) = 4/cor-1 . By (35), we have k(r) = 0 ( r _1), r —» + 00. Let D ^ be a hyperbolic disc which touches the euclidean circle C qiP from the inside. Then 0 ^ if and only if

p > T * p (=(cosh(D) ')• Furthermore, if this condition holds, the euclidean distance from D ^ to the origin is Pr = [\p,0],0] > [p. 2/5] = pr- It follows that l^J C {pT < |x| < 1}.

M n > p Now (37) implies (31) and Lemma 14 is proved.

Proof of Lemma 6. For R > r and A(r) = rT'(r) (see [12]) we have

T{R) = ^ ^ d t ~ f r ^ dt ~ ln 7 ^

R T{R) > N(R) = [ ^-dt> j ^-dt> n(r)ln J l t J r t r choosing R — r0(r) > rk and using (14), we obtain

A ir) const . n(r) const W ) ~ M M (39) Since cu decreases, applying (39), after an integration by parts, we obtain that the two integrals

r ^ f \ d n ( r ) and f ° ° dr (40) Ji T(r) V A T(r) T(r) r converge or diverge simultaneously. The proof in the subharmonic case is similar with T replaced by B and A(r) by rB'{r). This proves that (8) follows from (15). A similar argument holds in the case when u is increasing and (15) and (16) hold.

Now assume that u increases and that (17) holds. For non-constant w we have lim infr^oo T (r)/ln (r) > 0 (see [13]). Again integrating by parts we obtain

f ° ° uj , /*°° io _ noj f°° n f°° nuj const. / — d n < / -— dn - -— ,— du> + / -----dr . (41) Ji T ~ J1 lnr lnr 1 J 1 lnr J1 rln2r V 7 Taking R = r2 in (38), we see that n(r) < T (r2)/ln r - hence the convergence of the last integral in (41) follows from (17). Furthermore, we have

riU^— ds > n(r)u(r)/2 ln r. /' sin s Consequently, n(r)uj(r)/ lnr —> 0 as r —> oo. It is now clear that (8) follows from (17). If u> increases, (17) holds and u is non-constant, we have lim inf^oo B (r)/In r > 0. A similar argument shows that (10) follows from (17). This completes the proof of Lemma 6. SMALL SUBHARMONIC AND <5-SUBHARMONIC FUNCTIONS 83

P ro o f o f Theorem 1. Let (i be the Riesz measure of the function u, let rn > 1 be given numbers, and let the number q be such that for every large natural number n (n > n\) 1 \ (2 cosh( T ) ) • (42)

Define rn — qn+2 and e = U^Lien where for n > 1

en = {x G Drn : u^(z,rn) > Tn} n {qn < |z| <

For pn — qn and every large n (n > n2), we have the inequality Pn > rn ( cosh(rn/3)) 1 and hence from (31)

Cl C9rn(en) < — fi{In) (n > n2) (44) Tn where the constant c\ does not depend on n and

In = {0nqn+2 < M < qn+2}, 0n = [q~2, 2 ^cosh ( y ) ) ]• (45)

Since en C {qn < |x| < qn+1}, then for every £, 77 G en we have 5(C, r?, rn) - In < C2 (=\n2q2).

From (2) and (27) it follows easily that

c m > i + with some positive constant C3 (= (1 + C2)-1 ). From (44), we have

7 f (en) < — V{ln) (n > n2). (46) Tn where again the constant C4 > 0 does not depend on n. Let 9 G (0,1) be the number in the statement of the theorem and let

1 + 9 ( A*r\ 9 = — 9 - (47) Below we let rn —► 00. Thus for n\ sufficiently large we know that (42) holds for n > n Let &q be the set e defined above using (43). We define also !h = {^n_1 < \x\ < qn+2}. Assume that (8) holds for a given function w. Then there exists a function <7i (r) = o(l) (r —► 00) and numbers an = max{cri(r) : r G /* } such that

/ „ /u \ du(x) < °°> lim °nT{qn+2) = + 00. (48) J |*|

In (42) and (45), we choose rn = crnT(qn+2). It is easy to check that lim n -^ 9n — q~2. Thus, for n > we have q~3 < 9n < 1. Hence from (46)

V (e „) < — **(£)• (49) Tn 84 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN

We have proved that

Since the system of rings has finite multiplicity, it follows from (7) and (8) that the series in (4) is convergent. Let us now prove inequality (9). If x G C is an arbitrary point, then we have according to the Poisson-Jensen formula in D r that

w(x) = I(x) — wM(x,r) -|- uu(x ,r) > /(x ) — u^(x,r), (51) where 1 /»27T -j /»27T 1 /*27T H x ) = 7T~ / w(rel^)Pd(j) = — / w+ Pd(j) — — / w+ Pd(j) (52) Jo 2tt Jq 27t /q and P = P(x, r, 0) is the Poisson kernel:

r- w

w(x) > - — m+(r, u;) — m+ (r, m) — it^(x, r). (53) r + |x| r — |x|

If now x ^ e is an arbitrary point, there exists n = n(x) (n(x) —> +oo) such that qn < \x\ < qn+1 and x ^ en; from (53) with r — rn — qn+2 we have

Vn |-{ > 0, Vn + p j < O '1, u ^{x,rn) < r n —

w(x) > 6m + (rn, w) — 9~1m +(rn, w) — anT (rn).

Dividing by T(rn) and letting x —* oo outside e, we obtain (9). This concludes the Proof of Theorem 1.

P ro o f o f T heorem 2. Assume that (10) holds for a given function u. Then there exists a function 02(f) = o(l) (r —» oo) and numbers an — max{02(r) : r G /* } such that

/ -..* h < °°» lim anB(qn+2) = +oo. J\x\

In (42), (43) and (45), we choose rn = crnB(qn+2) in the same way as in the Proof of Theorem 1 to obtain the convergence of the series in (4). Let us now prove inequality (11). Using the inequality N(r) < B(r) and (51) we have that for all x G D r

1 r2n I(x) = B(r) — — / (B(r) — u(rel(^))Pd(f) > 2tt Jo

B - uW))d

(55) SMALL SUBHARMONIC AND <5-SUBHARMONIC FUNCTIONS 85

Again, it follows from (51) and (55) that for all x £ D r _ r+\x\ f _ N(r)\ u(x) > B{r) — wM(x, r). (56) r - N l B (r)J If x 0 e then there exists n = n(x) such that qn < |x| < qn+1 and x $ en; from (56) with r — rn — qn+2, we obtain

rn + \x\ < 9 , u^(x,rn) < r n = anB(rn). (57) rn ~ FI It follows from (56) that

3-1 N (rn) u(x) > B (rn) 1 - 1 - & nB (Tn) • B (rn) Dividing by B (rn) and letting x —> oo outside e, we obtain (11). This concludes the Proof of Theorem 2.

P ro o f o f T heorem 4. Assume that (12) holds for a given function u. In (42) and (45), we choose rn = c where c is such that 9n = [q~2, 2(cosh(c/3)) ] > q~3. From (46), we see that

uj(qn+2) ^ ( e n) < c5u;(gn+2)^ (/i) < c5 [ ujdfx. JII Now (12) gives us the convergence of the series from (4). To prove equation (13), we assume that x £ e. Arguing as in the proof of Theorem 2, we define numbers n = n(x). From (56) with r — rn = qn+2, we obtain that for qn < |rr| < qn+1,

u(x) > B (rn) - (B (rn) - N (rn)) - u ^(x,rn).

Using the assumption B = N + 0(1) from the formulation of theorem and the fact that u^(x, rn) < rn = c for x e, we see that u(x) > B (rn) + 0(1) > B(\x\) + 0(1) x —> oo, x £ e, and (13) is proved. Theorem 4 is proved. In the proofs of the corollaries, we need some facts about functions of small order (cf. Section 3.5 in [3]). If u has order zero, then B {r ) < N(r) + Q(r), where OO / t~ 2n(t)dt. (i) If 1 < a < 2 and B(r) = 0(lnar), r—> oo, (58)

then Q (r) = 0 ((ln r )a_1), and N (r )/B (r ) —»• 1 as r —* oo (note that N(r) < B{r) and that liminfr_>oo B ( r )/ln r > 0).

(ii) If n(oo) is finite, then Q (r) tends to zero as r —> oo and hence B(r) — iV(r) + o(l), r —> oo. (59) 86 A. YU. SHAHVERDIAN, M. ESSEN AND G.S. HOVANESSIAN

Proof of Corollary 9. If (58) holds, it is easy to see that (17) holds for uj(r) — In'3 r (0 < (3 < 2 — a). It follows from Lemma 6 that inequality (10) holds as well. Prom the remarks above, it is clear that d(u) — 0 and (21) follows from Theorem 2. We have proved Corollary 9.

Proof of Corollary 10. From (19), we see that there exist increasing functions ujo satisfying (22). Furthermore, it is clear from (19) and (22) that (10) holds with a;(r) = u>o(r) lnr. Again, we have d(u) = 0 (cf. (59)) and we can deduce (23) from Theorem 2. It is clear that (24) follows from Theorem 4. This concludes the Proof of Corollary 10.

Proof of Corollary 11. Since fOO wM( 0) = / In rdn(r) Jo is finite, we see that (22) holds with co(r) = lnr (in particular we have //(C) < oo) and (24) follows from Corollary 10. From (59) we have B (r ) = n(r)lnr + 0(l) and (26) follows from Theorem 4. Corollary 11 is proved.

Appendix A Modified Logarithmic Capacity. The following modified logarithmic capacity 7 (e), defined for subsets e C Co = C\{0}, was introduced in [18-21]. We consider compact sets e and the energy integral

7(/i,e) = II In d^(z)d(i(i) (60) where //, is a positive Borel measure with total mass 1 and with suppji C e (this convention holds throughout this section). Let

Vi(e) = inf /(/i,e).

We define

We shall also need the classical energy integral

J(//,e) = and let Vj{e) = inf J(/i,e).

The logarithmic capacity cap(e) is defined by cap(e) = exp{—Vj(e)} (cf. [1]): it is related to the classical logarithmic potential

Ufi(*) = Jeln \z-£\d> SMALL SUBHARMONIC AND 5-SUBHARMONIC FUNCTIONS 87

Since 0 0 e, it is easy to see that there exists a measure /i/ such that V/(e) = /(///, e) (cf. [5]). We claim that

z ) = \ J ln | 2 dto(£) = V/(e) q.e. on e, (62) where q.e. means quasi everywhere, i.e. outside a set of outer logarithmic capacity zero. In the discussion of our new capacity 7 (e), the function u(fi,z) and the sym­ metrized form of the energy integral /(//, e) play the same role as and J(p,, e) did in the discussion of cap(e) (cf. [5]). We use the same variational argument as in the proof of Theorem III.3 in [5], applied to our energy integral which can be written in the symmetric form

1. If u(fii,z) < Vi(e) — e on a set T C e where £ is positive and cap(T) > 0, we let r be a distribution of unit mass on T such that u(r, z) < K on e and let Us — (1 — S)fii -I- St for 0 < S < 1. Then //5(e) = 1, su p p ^ C e and

l(p.s, e) = (1 - 5)2I(f!,, e) + 26 J u ( m , z)dr(z) + 0(S 2)

< (1 - 26)V,(e) + 26(V,(e) - e) + 0(S2) < V>(c),

if 5 > 0 is small enough. This is impossible and we conclude that u (pi,z) > Vi(e) everywhere on e except on a set of zero capacity.

2. Conversely, if u (iii,z0) > V/(e) for some zq G supp/i/, then u (ni,z) > V/(e) on a neighborhood of zq of positive ///-measure which contradicts the fact that

7(/z/,e) = J^u{m,z)d^I(z) = Vr(e).

We have proved that (62) holds.

Theorem 15. Let d = dist.(0,e) > 0. Then

V,(e) = K/(e) + lnd+i A n(|£|/d)dW (£). (63)

Corollary 16. V/(e) > ln (d/cap(e)).

Proof of Corollary 16. This is clear since V j(e) = — lncap(e) and the integral in Theorem 15 is nonnegative.

Proof of Theorem 15. Let Cl be the unbounded component of C \ e. Let g be Green’s function in with a pole at infinity: g is harmonic in £7, vanishes on and its asymptotic behaviour at infinity is of the form g(z) = ln\z\+p(Cl) + £(z), where p(n) is Robin’s constant and £(z) —> 0 as 2 —» oo. Let H be a in fl vanishing at infinity with boundary values ln(|z|/

It follows from (62) that G (z) vanishes q.e. on e. Furthermore, as z —> oo,

~ lG(z) = ln\z\ + \ (2VHe) - t o d - ^ln|£|d/i/(0 ), and it follows that we have g(z) = —G ( z ) /2 and thus that

= V,(«)-| jfln(|C|/d)dW(0 .

From [1], we know that p(Q) = Vj(e). We have proved Theorem 15. □

Proposition 17. Lei max2£e |z| = D . If cap(e) < d, then

(in (D /cap(e))) 1 < 7 (e) < ^ln (d/cap(e)) . (64)

P roof. From Theorem 15, we see that

In (d/cap(e)) < V/(e) < In (d/cap(e)) + ^ In[D /d) < In (D/cap(e)), which proves Proposition 17. □

Rem ark 18. This kind of estimate is of interest when we know apriori that our set e is contained in an annulus A n = {z G C : qn < \z\ < gn+1} for a given number q > 1 and an integer n. If 7 (e) is small, it follows from Proposition 17 that cap(e) must be small. Since D /d < q, we deduce from (64) that

(in (7 + In (d/cap(e))) 1 < 7 (e) < ^ln (d/cap(e)) 1 j .

In the case when 0 G H, we can also estimate 7 (e) in terms of g(0). From [1], we know that

g{ 0) = \n(\/cap(e))+ j\n\Z\dnj{£)i and it follows that

In (d/cap(e)) < g(0) < In (D /cap(e)).

In the case of an annulus discussed above with 7 (e) small, we deduce that

(#( 0) + lng) _1 < 7 (e) < (g(0) - lng)_1.

We note that if V/(e) is large, In ( 0) in the complex plane, it is often sufficient to check a normalized case. (i) If L is an arc of a circle centered at the origin of angular measure ip G (0,2n), then cap(L) = rsin(<^/4) and

7 (L) - (In {r/cap{L)~1)) = (in (l/s in (cp/4)))- 1 . SMALL SUBHARMONIC AND .5-SUBHARMONIC FUNCTIONS 89

(ii) All circles C — {z e C \ \z — £| < r} touching both sides of a given angle in C with vertex at the origin and opening ip € (0,7r) have the same 7-capacity. Without loss of generality, we choose |£| = 1. Then

d = 1 — sin (

( In ( 1 + ^ M S ’V) ' < 7(C) < f In f 1 Sta (%{2)) \ \ sm(y>/2) )) V V sm(v?/2) 7

(iii) Let S' be a rectilinear segment [a, 6] on the real line with 0 < a < b. Then cap(S') = (b — a )/4 and

46 \ \ -1 /, / 4a x x _1 In ------< 7 (5 ) < In b — a J J \ \b — a

For large sets e, Vj(e) can be negative. As an example, we consider e = {z E C : 1 < \z\ < R } and claim that V/(e) = — lni?/4. Since Vj(e) is finite, it follows from Theorem 15 that Vjr(e) is finite and there exists a minimizing measure. Due to the radial symmetry of the set e, it suffices to consider measures of the form

d/j,(z) = dv(r) x (d 0/27r), n(e) — 1. A computation shows that

f R J(/i,e) = J (u(r)2 - v(r))dr/i

It is easy to see that V/(e) is assumed if u(r) is defined by

z^(l) = 0, u(r) = 1/2, 1 < r < R, u(R) = 1,

and we see that V7(e) = — In R/A. The support of the minimizing measure is contained in the circles {|^| = 1} and {|z| = R}.

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M. Essen A. Yu. Shahverdian Department of Mathematics Yerevan Physics Institute Uppsala University Alikhanian Brothers Str. 2 375036 PO Box 480 Yerevan S-751 06 Uppsala ARMENIA Sweden svrdn@jerewanl .yerphi.am EUROPE [email protected]

G.S. Hovanessian Gyumri Branch of Yerevan Engineering University M. Mkrtchyan Str. 2 377503 Gyumri ARMENIA seuagec@shirak. am