Chemical Kinetics

Total Page:16

File Type:pdf, Size:1020Kb

Chemical Kinetics 4 Chemical Kinetics To understand the physical Thermodynamics teaches us about the energetics and favorability of reac- Goal factors that determine reac- tions but not whether they are fast or slow. For that we need to understand tion rates. kinetics, the study of rates of reactions and the physical factors that influ- ence those rates. Reactions that are thermodynamically favorable can take Objectives millions of years to reach equilibrium. In fact, the velocities of favorable After this chapter, you should be able to: reactions vary over about fifteen orders of magnitude. The speed of reac- tions is critically important for living systems, which must ensure that they • describe the factors that determine reaction rates. occur rapidly enough to be consistent with the rates at which cells grow and divide. Consequently, cells have evolved strategies to accelerate reactions • identify nucleophile, electrophile, and so that they occur on a biological timescale. In this chapter we will exam- leaving group. ine the factors that influence reaction rates, and in later chapters, we will • use arrow pushing to represent reaction explore the strategies that living systems use to increase and control those mechanisms. rates. • draw and interpret reaction energy diagrams. Reaction rates are determined by the frequency, orientation, and energy • draw transition states. with which molecules collide • write a rate expression for a simple Molecules have a characterize size, shape, and distribution of electrons. As chemical reaction and explain how the rate is related to ΔG‡. such, a reaction between two molecules can only occur when they physically contact each other; they must collide to react. The rate at which molecules react with each other to form product (or deplete reactant) is determined by the frequency with which they collide, the probability that they collide in an orientation that allows the reaction to occur, and the probability that the molecules that collide do so with enough energy for the reaction to take place. Chapter 4 Chemical Kinetics 2 Probability that Probability that reaction concentration of velocity of cross sectional area of = x x x molecules collide in x molecules collide with rate reactant molecules reactant molecules reactant molecules the right orientation enough energy to react Figure 1 Reaction rates depend on multiple factors Not every collision leads to a reaction, but the rate of a reaction depends on the frequency with which reactant molecules collide, which is influenced by the concentration of the reactants (Figure 1). The larger the number of reactant molecules that are confined within a given volume, the greater the probability of their colliding. The rate of reaction is also influenced by the velocity of the reactant molecules, which again influences the frequency of collisions. The rate of reaction also depends on the cross-sectional area of the reactant molecules, a property determined by the shape and size of the molecules involved in the reaction. Reactions can only occur between parts of molecules that are capable of forming new bonds; therefore, the rate of a reaction also depends on the probability that individual molecules collide in the appropriate orientation to react (Figure 1). However, colliding in a productive orientation is not sufficient. Individual molecules also need to collide with enough energy to react. As we have seen, breaking bonds requires energy, and because all reactions involve the breaking of bonds, an input of energy is required to overcome this energetic barrier (or “threshold of free energy” as we will see below). Even for a favorable reaction in which the products are lower in energy than the reactants, some amount of energy is necessary to overcome this energetic barrier and initiate the bond breaking reaction. The rate of a reaction is influenced by temperature, an insight that was formalized by the scientist Svante Arrhenius in the late 1800’s. Temperature increases the frequency with which molecules collide by influencing the velocity of the reactant molecules and the proportion of molecules with sufficient energy to overcome the energetic barrier to react (see Box 1). Therefore, temperature influences two of the five factors in Figure 1, velocity of reactant molecules and probability that molecules collide with enough energy to react. To better understand how the five factors influence the rate of reactions, we need to understand how reactions proceed, that is, the sequence of events or pathway by which reactions proceed. The reaction pathway can be represented in two complementary ways: by a molecular mechanism and by a reaction energy diagram. These representations allow us to derive rules that predict reaction outcomes. An arrow pushing formalism describes reaction mechanisms Put simply, a chemical reaction is a rearrangement of valence electrons that leads to the cleavage and/or formation of bonds. The specific electron movements associated with each reaction are described by the reaction mechanism. Reaction mechanisms show where electrons originate in the reactant and where they ultimately reside in the product. This is represented Chapter 4 Chemical Kinetics 3 Box 1 The Boltzmann Distribution Energy is not distributed evenly among molecules in a system, and if you were to examine each individual molecule at any moment, you would find that some molecules have more energy than others. As a con- sequence, some molecules may have enough energy to react upon colliding, whereas others may not. As temperature increases, however, so does the probability that molecules in the system have enough energy to react. The Boltzmann distribution describes the probability that a molecule will occupy a specific energy level. Shown below are three simple plots of Boltzmann distributions at different temperatures. Each bar rep- resents the probability of a molecule at that temperature having the indicated energy level (the taller the bar, the higher the probability). Bars further to the right indicate higher energy levels. energy needed to react low temperature medium temperature high temperature increasing energy As you can see, at the “low” temperature it is likely that the molecule is at a low energy level, and there is little chance that it has enough energy to react (as indicated by the dotted line). As temperature increases, how- ever, so does the probability that the molecule has enough energy to react. At the “medium” temperature, there is a small chance that a molecule has enough energy to react. At the “high” temperature, the likelihood of a molecule possesses enough energy to react is much higher. graphically using a formalized system called arrow pushing in which the movement of electrons is diagrammed using a series of curved arrows. Arrow pushing diagrams adhere to the following rules: 1. Each arrow represents the movement of one pair of valence electrons. 2. Each arrow begins where the electrons originate (either a lone pair of electrons or a bond) and ends where the electrons are going (either an atom or a bond). 3. An arrow that starts at an atom represents the movement of a lone pair of electrons. 4. An arrow that starts at the center of a bond represents the breaking of that bond. 5. An arrow that ends at an atom represents the formation of a new covalent bond or a new lone pair. 6. An arrow that ends at a bond represents adding of a bond to form a double (or triple) bond. Applying the rules of arrow pushing so that they become second nature requires practice. Box 2 shows examples of mechanisms that are described by individual arrows. Use arrow pushing to draw the reactions shown in the Boxes and then tackle the practice problems. Chapter 4 Chemical Kinetics 4 Box 2 Interpreting arrow pushing formalism Interpretation Generic Example Molecular Example An arrow pointing from a single bond to an atom means that the bond breaks and a lone pair forms on A B A B H Cl H Cl the target atom. An arrow pointing from a lone pair to an atom means that the lone pair electrons form a new bond to the B A A B Cl H H Cl target atom. An arrow pointing from a double or triple bond to an atom means that one of the bonds breaks, and those O O electrons form a new lone pair on the target atom. A B A B H H H H An arrow pointing from a lone pair to a bond means the lone pair electrons are used to increase the bond O O A B order of the target bond (e.g., a single bond becomes A B a double bond). H H H H As we saw in Chapter 2, many molecules contain atoms that carry full or partial charges. Reactions between molecules (small molecules or functional groups on macromolecules) often occur when the electrons from an atom carrying a negative charge (full or partial) forms a bond with an atom in another molecule that carries a positive charge (full or partial). For reactions in which a bond is formed between atoms that were not previously bonded, the electron-rich atom from which the electrons originate is known as the nucleophile and the electron-deficient, atom is known as the electrophile (Figure 2). As their names imply, nucleophiles are attracted to nuclei and electrophiles are attracted to electrons (philos being Greek for love). Another concept that is important in understanding reaction mechanisms is the leaving group. This term is used to describe an atom or portion of a molecule that separates from a molecule as a result of a bond breaking during the course of a reaction. Leaving groups always take both electrons from the broken bond with them as they depart. Nucleophile, electro- Figure 2 (A) Nu E phile, and leaving group describe Nu E specific atoms in reaction mecha- Nucleophile Electrophile nisms (A) Shown is a generic reaction of a nucle- H O H H O H ophile with an electrophile (top) and a spe- cific example involving a reaction between hydroxide and a hydrogen ion (bottom).
Recommended publications
  • Transition State Theory. I
    MIT OpenCourseWare http://ocw.mit.edu 5.62 Physical Chemistry II Spring 2008 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms. 5.62 Spring 2007 Lecture #33 Page 1 Transition State Theory. I. Transition State Theory = Activated Complex Theory = Absolute Rate Theory ‡ k H2 + F "! [H2F] !!" HF + H Assume equilibrium between reactants H2 + F and the transition state. [H F]‡ K‡ = 2 [H2 ][F] Treat the transition state as a molecule with structure that decays unimolecularly with rate constant k. d[HF] ‡ ‡ = k[H2F] = kK [H2 ][F] dt k has units of sec–1 (unimolecular decay). The motion along the reaction coordinate looks ‡ like an antisymmetric vibration of H2F , one-half cycle of this vibration. Therefore k can be approximated by the frequency of the antisymmetric vibration ν[sec–1] k ≈ ν ≡ frequency of antisymmetric vibration (bond formation and cleavage looks like antisymmetric vibration) d[HF] = νK‡ [H2] [F] dt ! ‡* $ d[HF] (q / N) 'E‡ /kT [ ] = ν # *H F &e [H2 ] F dt "#(q 2 N)(q / N)%& ! ‡ $ ‡ ‡* ‡ (q / N) ' q *' q *' g * ‡ K‡ = # trans &) rot ,) vib ,) 0 ,e-E kT H2 qH2 ) q*H2 , gH2 gF "# (qtrans N) %&( rot +( vib +( 0 0 + ‡ Reaction coordinate is antisymmetric vibrational mode of H2F . This vibration is fully excited (high T limit) because it leads to the cleavage of the H–H bond and the formation of the H–F bond. For a fully excited vibration hν kT The vibrational partition function for the antisymmetric mode is revised 4/24/08 3:50 PM 5.62 Spring 2007 Lecture #33 Page 2 1 kT q*asym = ' since e–hν/kT ≈ 1 – hν/kT vib 1! e!h" kT h! Note that this is an incredibly important simplification.
    [Show full text]
  • Transition State Analysis of the Reaction Catalyzed by the Phosphotriesterase from Sphingobium Sp
    Article Cite This: Biochemistry 2019, 58, 1246−1259 pubs.acs.org/biochemistry Transition State Analysis of the Reaction Catalyzed by the Phosphotriesterase from Sphingobium sp. TCM1 † † † ‡ ‡ Andrew N. Bigley, Dao Feng Xiang, Tamari Narindoshvili, Charlie W. Burgert, Alvan C. Hengge,*, † and Frank M. Raushel*, † Department of Chemistry, Texas A&M University, College Station, Texas 77843, United States ‡ Department of Chemistry and Biochemistry, Utah State University, Logan, Utah 84322, United States *S Supporting Information ABSTRACT: Organophosphorus flame retardants are stable toxic compounds used in nearly all durable plastic products and are considered major emerging pollutants. The phospho- triesterase from Sphingobium sp. TCM1 (Sb-PTE) is one of the few enzymes known to be able to hydrolyze organo- phosphorus flame retardants such as triphenyl phosphate and tris(2-chloroethyl) phosphate. The effectiveness of Sb-PTE for the hydrolysis of these organophosphates appears to arise from its ability to hydrolyze unactivated alkyl and phenolic esters from the central phosphorus core. How Sb-PTE is able to catalyze the hydrolysis of the unactivated substituents is not known. To interrogate the catalytic hydrolysis mechanism of Sb-PTE, the pH dependence of the reaction and the effects of changing the solvent viscosity were determined. These experiments were complemented by measurement of the primary and ff ff secondary 18-oxygen isotope e ects on substrate hydrolysis and a determination of the e ects of changing the pKa of the leaving group on the magnitude of the rate constants for hydrolysis. Collectively, the results indicated that a single group must be ionized for nucleophilic attack and that a separate general acid is not involved in protonation of the leaving group.
    [Show full text]
  • Often an Acidic Proton)
    314 Arrow Pushing practice/Beauchamp 1 Electrophile = electron loving = any general electron pair acceptor = Lewis acid, (often an acidic proton) Nucleophile = nucleus/positive loving = any general electron pair donor = Lewis base, (often donated to an acidic proton) Problems - In the following reactions each step has been written without the formal charge or lone pairs of electrons and curved arrows. Assume each atom follows the normal octet rule, except hydrogen (duet rule). Supply the lone pairs, formal charge and the curved arrows to show how the electrons move for each step of the reaction mechanism. Identify any obvious nucleophiles and electrophiles in each of the steps of the reactions below (on the left side of each reaction arrow). A separate answer file will be created, as I get to it. Let me know when you find errors. RX reactions Examples of important patterns to know from our starting points (plus a few extras). methyl and primary secondary tertiary special H3C X very good very poor SN2 patterns SN2,E2,SN1,E1 X X X X X vinyl allylic X X X X X X X benzylic X phenyl X X There are many X variations. X 1o neopentyl 1. SN2 and SN2 a b I Br Br N C I I C I N 2. SN2 and E2 a b H Br H O HC C H I HC C Br OH I 3. SN2 and SN2 a Na b Na Na Br S HC C Br Br O O S Na Br R R Z:\classes\315\315 Handouts\arrow pushing mechs, probs.doc 314 Arrow Pushing practice/Beauchamp 2 4.
    [Show full text]
  • Arrow Pushing: Mechanisms
    Arrow Pushing: Mechanisms A few rules to follow: X H H 1) Arrows show the movement of ELECTRONS! HO HO They go from site of high electron density, usually a lone pair or alkene, to sites of low electron density, Correct OTs Incorrect OTs usually a cation, hydrogen, or unfilled orbital. H H H H 2) Balance the equation. Be sure to conserve mass and charge. If you start with an over charge of +1, +1 Incorrect 0 you need to end with an overall charge of +1. +1 Correct +1 Br Br CN Br CN Br H H 3) Draw out all intermediates. Include hydrogens, lone CN NC pairs, and charges. Be sure there are no carbons with X Incorrect H 5 bonds or other chemical errors in the intermediates. Correct 5 bonds to C OH Cl Cl HCl 4) The mechanism should give the observed product. + Do not forget about stereochemistry and regiochemistry. This mechanism HAS to go via a SN1 Let's try an example: HO cat. TsOH Given this reaction scheme we can determine that this will be an elimination type mechanism, specifically E1. CH HO CH3 2 The reaction scheme may not show all by products! CH CH3 cat. TsOH 3 + H2O Let's draw all hydrogens and balance the equation. H The lone pair on oxygen would be a site of high electron HO CH3 O CH3 O H O density and an acidic hydrogen (TsOH) is a site of low OH + OH CH3 H S CH3 S electron density. Note: TsOH is catalytic so it needs to O O O O be regenerated in our mechanism! H Now that we have made a charged species we want to CH H O CH3 3 find a way to stabalize or neutralize the charge.
    [Show full text]
  • Lecture Outline a Closer Look at Carbocation Stabilities and SN1/E1 Reaction Rates We Learned That an Important Factor in the SN
    Lecture outline A closer look at carbocation stabilities and SN1/E1 reaction rates We learned that an important factor in the SN1/E1 reaction pathway is the stability of the carbocation intermediate. The more stable the carbocation, the faster the reaction. But how do we know anything about the stabilities of carbocations? After all, they are very unstable, high-energy species that can't be observed directly under ordinary reaction conditions. In protic solvents, carbocations typically survive only for picoseconds (1 ps - 10–12s). Much of what we know (or assume we know) about carbocation stabilities comes from measurements of the rates of reactions that form them, like the ionization of an alkyl halide in a polar solvent. The key to connecting reaction rates (kinetics) with the stability of high-energy intermediates (thermodynamics) is the Hammond postulate. The Hammond postulate says that if two consecutive structures on a reaction coordinate are similar in energy, they are also similar in structure. For example, in the SN1/E1 reactions, we know that the carbocation intermediate is much higher in energy than the alkyl halide reactant, so the transition state for the ionization step must lie closer in energy to the carbocation than the alkyl halide. The Hammond postulate says that the transition state should therefore resemble the carbocation in structure. So factors that stabilize the carbocation also stabilize the transition state leading to it. Here are two examples of rxn coordinate diagrams for the ionization step that are reasonable and unreasonable according to the Hammond postulate. We use the Hammond postulate frequently in making assumptions about the nature of transition states and how reaction rates should be influenced by structural features in the reactants or products.
    [Show full text]
  • Property Relationships Acid-Base Chemistry W
    109, Structure & Properties, Acid-Base CHEM 109, Lecture 1 Structure – Property Relationships Acid-Base Chemistry McMurry & Begley (M&B) Chapter 1.1-1.2 (posted on CHEM 109 website) CONCEPT MAP: CHEMICAL STRUCTURE & PROPERTY RELATIONSHIPS WHAT DO WE KNOW WELL & WHAT COULD WE KNOW BETTER? The intention of this exercise is to figure out your current knowledge of the relationship between chemical structures and properties. Perhaps more importantly, we want to identify misconceptions or gaps in knowledge. Learning that you don’t understand something as well as you thought is actually a good thing! This will be based on your knowledge and, eventually, that of your peers. No outside resources such as cell phones, notebooks, textbooks, etc. are necessary. Before Class: Cut out each term on page E1-3 to create a set of cards. Begin to categorize and relate the fundamental general chemistry terms to each other by moving the term cards around. Brainstorm your current understanding of each term on a separate sheet of paper. Draw structures and/or figures to exemplify the term where appropriate (this is appropriate for most terms). Create a concept map (example on next page) with these terms – use the cards, write the terms by hand, or use a digital format such as ThinkSpace or Mindmeister. Add terms and links as necessary to complete your map. There are many, many ways to organize and describe these terms. Do what make sense to you! I can’t stop you from looking up terms on your own, but I’d recommend avoiding this as much as possible.
    [Show full text]
  • CH4103 Organic and Biological Chemistry LCM Lecture 5
    CH4103 Organic and Biological Chemistry LCM Lecture 5 Dr Louis C. Morrill School of Chemistry, Cardiff University Main Building, Rm 1.47B [email protected] Autumn Semester For further information see Learning Central: CH4103/Learning Materials/LCM 1 Lecture 5 Preparation To best prepare yourself for the contents of this lecture, please refresh • Atomic and molecular orbitals (Unit 1, Lecture 2) • Molecular shape and hybridisation (Unit 1, Lecture 2) • Sigma and pi bonds (Unit 1, Lecture 2) • Electronegativity and bond polarisation (Unit 1, Lecture 3) • Stereochemistry (Unit 1, Lecture 4-7) • Reactive intermediates – carbocations (Unit 1, Lecture 8) • Acids and bases – pKa (Unit 1, Lecture 9) • Reaction thermodynamics (Unit 2, Lecture 1) and kinetics (Unit 2, Lecture 2) • Curly arrow pushing mechanisms (Unit 2, Lecture 3) and SN2 (Unit 2, Lecture 4) For further information see Learning Central: CH4103/Learning Materials/LCM 2 Lecture 5: Introduction to Substitution Reaction – SN1 Key learning objectives: • Know the difference between the possible mechanisms for nucleophilic substitution at saturated carbon – SN2 and SN1 • The rate law for a SN1 reaction • The free energy diagram for a SN1 reaction • The curly arrow pushing mechanism, molecular orbital analysis, intermediate and stereochemical outcome of a SN1 reaction • The factors that favour a SN1 mechanism including the nature of the substrate, nucleophile, solvent and leaving group • Synthetic Analysis – How to favour one substitution mechanism over the other? For further information
    [Show full text]
  • Glossary of Terms Used in Photochemistry, 3Rd Edition (IUPAC
    Pure Appl. Chem., Vol. 79, No. 3, pp. 293–465, 2007. doi:10.1351/pac200779030293 © 2007 IUPAC INTERNATIONAL UNION OF PURE AND APPLIED CHEMISTRY ORGANIC AND BIOMOLECULAR CHEMISTRY DIVISION* SUBCOMMITTEE ON PHOTOCHEMISTRY GLOSSARY OF TERMS USED IN PHOTOCHEMISTRY 3rd EDITION (IUPAC Recommendations 2006) Prepared for publication by S. E. BRASLAVSKY‡ Max-Planck-Institut für Bioanorganische Chemie, Postfach 10 13 65, 45413 Mülheim an der Ruhr, Germany *Membership of the Organic and Biomolecular Chemistry Division Committee during the preparation of this re- port (2003–2006) was as follows: President: T. T. Tidwell (1998–2003), M. Isobe (2002–2005); Vice President: D. StC. Black (1996–2003), V. T. Ivanov (1996–2005); Secretary: G. M. Blackburn (2002–2005); Past President: T. Norin (1996–2003), T. T. Tidwell (1998–2005) (initial date indicates first time elected as Division member). The list of the other Division members can be found in <http://www.iupac.org/divisions/III/members.html>. Membership of the Subcommittee on Photochemistry (2003–2005) was as follows: S. E. Braslavsky (Germany, Chairperson), A. U. Acuña (Spain), T. D. Z. Atvars (Brazil), C. Bohne (Canada), R. Bonneau (France), A. M. Braun (Germany), A. Chibisov (Russia), K. Ghiggino (Australia), A. Kutateladze (USA), H. Lemmetyinen (Finland), M. Litter (Argentina), H. Miyasaka (Japan), M. Olivucci (Italy), D. Phillips (UK), R. O. Rahn (USA), E. San Román (Argentina), N. Serpone (Canada), M. Terazima (Japan). Contributors to the 3rd edition were: A. U. Acuña, W. Adam, F. Amat, D. Armesto, T. D. Z. Atvars, A. Bard, E. Bill, L. O. Björn, C. Bohne, J. Bolton, R. Bonneau, H.
    [Show full text]
  • Spring 2013 Lecture 13-14
    CHM333 LECTURE 13 – 14: 2/13 – 15/13 SPRING 2013 Professor Christine Hrycyna INTRODUCTION TO ENZYMES • Enzymes are usually proteins (some RNA) • In general, names end with suffix “ase” • Enzymes are catalysts – increase the rate of a reaction – not consumed by the reaction – act repeatedly to increase the rate of reactions – Enzymes are often very “specific” – promote only 1 particular reaction – Reactants also called “substrates” of enzyme catalyst rate enhancement non-enzymatic (Pd) 102-104 fold enzymatic up to 1020 fold • How much is 1020 fold? catalyst time for reaction yes 1 second no 3 x 1012 years • 3 x 1012 years is 500 times the age of the earth! Carbonic Anhydrase Tissues ! + CO2 +H2O HCO3− +H "Lungs and Kidney 107 rate enhancement Facilitates the transfer of carbon dioxide from tissues to blood and from blood to alveolar air Many enzyme names end in –ase 89 CHM333 LECTURE 13 – 14: 2/13 – 15/13 SPRING 2013 Professor Christine Hrycyna Why Enzymes? • Accelerate and control the rates of vitally important biochemical reactions • Greater reaction specificity • Milder reaction conditions • Capacity for regulation • Enzymes are the agents of metabolic function. • Metabolites have many potential pathways • Enzymes make the desired one most favorable • Enzymes are necessary for life to exist – otherwise reactions would occur too slowly for a metabolizing organis • Enzymes DO NOT change the equilibrium constant of a reaction (accelerates the rates of the forward and reverse reactions equally) • Enzymes DO NOT alter the standard free energy change, (ΔG°) of a reaction 1. ΔG° = amount of energy consumed or liberated in the reaction 2.
    [Show full text]
  • 2014 Purple Book Answers Week 4.Pdf
    Chem S-20ab Purple Book Solutions Week 4 - Page 1 of 38 Aromaticity 1. Given the following structures, circle any that are aromatic. Explain why the other species are not aromatic. 4n electrons not a continuous antiaromatic cyclic system. NH not a continuous 4n electrons cyclic system. antiaromatic 2. In the following molecule, which nitrogen atom is more basic (i.e. more willing to accept a proton)? Why? The other one has its lone pair as part of CH3 the 6 electron aromatic system. Protonating that lone pair would destroy the aromaticity, N which would be bad: H CH3 this one is more basic N N not a continuous cyclic system. N 3. When the following molecule is oxidized, the expected ketone is not formed, but phenol is formed instead. Describe what is going on here, and explain this unusual behavior. OH O OH CrO3 oxidation phenol Tautomerizes in order to achieve aromaticity. Chem S-20ab Purple Book Solutions Week 4 - Page 2 of 38 Electrophilic Aromatic Substitution: Mechanisms 1. Provide a curved-arrow mechanism for the following transformation. Show resonance structures for the cationic intermediate which make it clear why the substitution goes where it does. O O Cl HN CH3 HN CH3 AlCl3 catalyst Cl AlCl3 Cl AlCl3 O O O O HN CH3 HN CH3 HN CH3 HN CH3 H H H want to put + charge next to :Solvent electron-donating nitrogen 2. Provide a curved-arrow mechanism for the following transformation. H+ + O: H2SO4 catalyst H OH :Sol :Solvent OH2 H OH H+ OH OH Chem S-20ab Purple Book Solutions Week 4 - Page 3 of 38 Electrophilic Aromatic Substitution: Direction 1.
    [Show full text]
  • Reactions of Alkenes and Alkynes
    05 Reactions of Alkenes and Alkynes Polyethylene is the most widely used plastic, making up items such as packing foam, plastic bottles, and plastic utensils (top: © Jon Larson/iStockphoto; middle: GNL Media/Digital Vision/Getty Images, Inc.; bottom: © Lakhesis/iStockphoto). Inset: A model of ethylene. KEY QUESTIONS 5.1 What Are the Characteristic Reactions of Alkenes? 5.8 How Can Alkynes Be Reduced to Alkenes and 5.2 What Is a Reaction Mechanism? Alkanes? 5.3 What Are the Mechanisms of Electrophilic Additions HOW TO to Alkenes? 5.1 How to Draw Mechanisms 5.4 What Are Carbocation Rearrangements? 5.5 What Is Hydroboration–Oxidation of an Alkene? CHEMICAL CONNECTIONS 5.6 How Can an Alkene Be Reduced to an Alkane? 5A Catalytic Cracking and the Importance of Alkenes 5.7 How Can an Acetylide Anion Be Used to Create a New Carbon–Carbon Bond? IN THIS CHAPTER, we begin our systematic study of organic reactions and their mecha- nisms. Reaction mechanisms are step-by-step descriptions of how reactions proceed and are one of the most important unifying concepts in organic chemistry. We use the reactions of alkenes as the vehicle to introduce this concept. 129 130 CHAPTER 5 Reactions of Alkenes and Alkynes 5.1 What Are the Characteristic Reactions of Alkenes? The most characteristic reaction of alkenes is addition to the carbon–carbon double bond in such a way that the pi bond is broken and, in its place, sigma bonds are formed to two new atoms or groups of atoms. Several examples of reactions at the carbon–carbon double bond are shown in Table 5.1, along with the descriptive name(s) associated with each.
    [Show full text]
  • Computational Analysis of the Mechanism of Chemical Reactions
    Computational Analysis of the Mechanism of Chemical Reactions in Terms of Reaction Phases: Hidden Intermediates and Hidden Transition States ELFI KRAKA* AND DIETER CREMER Department of Chemistry, Southern Methodist University, 3215 Daniel Avenue, Dallas, Texas 75275-0314 RECEIVED ON JANUARY 9, 2009 CON SPECTUS omputational approaches to understanding chemical reac- Ction mechanisms generally begin by establishing the rel- ative energies of the starting materials, transition state, and products, that is, the stationary points on the potential energy surface of the reaction complex. Examining the intervening spe- cies via the intrinsic reaction coordinate (IRC) offers further insight into the fate of the reactants by delineating, step-by- step, the energetics involved along the reaction path between the stationary states. For a detailed analysis of the mechanism and dynamics of a chemical reaction, the reaction path Hamiltonian (RPH) and the united reaction valley approach (URVA) are an effi- cient combination. The chemical conversion of the reaction complex is reflected by the changes in the reaction path direction t(s) and reaction path curvature k(s), both expressed as a function of the path length s. This information can be used to partition the reaction path, and by this the reaction mech- anism, of a chemical reaction into reaction phases describing chemically relevant changes of the reaction complex: (i) a contact phase characterized by van der Waals interactions, (ii) a preparation phase, in which the reactants prepare for the chemical processes, (iii) one or more transition state phases, in which the chemical processes of bond cleavage and bond formation take place, (iv) a product adjustment phase, and (v) a separation phase.
    [Show full text]