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STABLE HYPERSURFACES WITH CONSTANT SCALAR CURVATURE

HILARIO´ ALENCAR, WALCY SANTOS AND DETANG ZHOU

Abstract. We obtain some nonexistence results for complete non- compact stable hyppersurfaces with nonnegative constant scalar curvature in Euclidean spaces. As a special case we prove that there 4 is no complete noncompact strongly stable hypersurface M in R with zero scalar curvature S2, nonzero Gauss-Kronecker curvature R 3 and finite total curvature (i.e. M |A| < +∞).

2000 Mathematics Subject Classification: Primary: 53042.

1. Introduction In this paper we study the complete noncompact stable hypersurfaces with constant scalar curvature in Euclidean spaces. It has been proved by Cheng and Yau [CY] that any complete noncompact hypersurfaces in the with constant scalar curvature and nonnegative sectional curvature must be a generalized . Note that the as- sumption of nonnegative sectional curvature is a strong condition for hypersurfaces in the Euclidean space with zero scalar curvature since the hypersurface has to be flat in this case. Let M n be a complete ori- n n+1 entable Riemannian and let x : M → R be an isometric n+1 immersion into the Euclidean space R with constant scalar curvature. We can choose a a global unit vector field N and the Riemannian n+1 connections ∇ and ∇e of M and R , respectively, are related by

∇e X Y = ∇X Y + hA(X),Y iN, where A is the second fundamental form of the immersion, defined by

A(X) = −∇e X N.

The authors were partially supported by CNPq and FAPERJ, Brazil. 1 2 Hil´arioAlencar, Walcy Santos and Detang Zhou

Let λ1, ..., λn be the eigenvalues of A. The r-mean curvature of the immersion in a p is defined by 1 X 1 Hr = n λi1 ...λir = nSr, r i1<...

Theorem A. (see Theorem 3.1) There is no complete noncompact sta- n+1 ble hypersurface M in R with zero scalar curvature S2 and 3-mean curvature S3 6= 0 satisfying R 3 S1 (1.2) lim BR = 0, R→+∞ R2 where BR is the geodesic ball in M. 2 2 When S2 = 0, S1 = |A| we have Stable hypersurfaces with constant scalar curvature 3

Corollary B. There is no complete noncompact stable hypersurface M 4 in R with zero scalar curvature S2, nonzero Gauss-Kronecker curvature R 3 and finite total curvature (i.e. M |A| < +∞). We remark that Shen-Zhu (see [SZ]) proved that a complete stable mini- n+1 mal n-dimensional hypersurface in R with finite total curvature must be a . The above Corollary can be seen as a similar result in 3 for hypersurfaces with zero scalar curvature. We also prove the following result for hypersurfaces with positive con- stant scalar curvature in Euclidean space. Theorem C. (see Theorem 3.2) There is no complete immersed strongly n n+1 stable hypersurface M → R , n ≥ 3, with positive constant scalar curvature and growth of 1-volume, that is R S1dM lim BR < ∞, R→∞ Rn

n where BR is a geodesic ball of radius R of M .

As a consequence of the properties of a graph with constant scalar curvature, we have the following corollary: n Corollary D. (see Corollary 4.1) Any entire graph on R with nonneg- ative constant scalar curvature must have zero scalar curvature. This can be compared with a result of Chern [Ch] which says any en- n tire graph on R with constant mean curvature must be minimal. It has been be known by a result of X. Cheng in [Che] (see also [ENR]) n+1 that any complete noncompact stable hypersurface in R with con- stant mean curvature must be minimal if n < 5. It is natural to ask that n+1 any complete noncompact stable hypersurface in R with nonnegative constant scalar curvature must have zero scalar curvature. It should be remarked that Chern[Ch] proved that there is no entire n graph on R with less than a negative constant. We n don’t know whether there exists an entire graph on R with constant negative scalar curvature. The rest of this paper is organized as follows: we include some results and definitions which will be used in the proof of our theorems in Section 2. The proof of main results are given in Section 3 and Section 4 is an appendix in which we prove some stability properties for graphs with constant scalar curvature in the Eucildean space. 4 Hil´arioAlencar, Walcy Santos and Detang Zhou

2. Some stability and index properties for hypersurfaces with S2 = const.

We introduce the r’th Newton transformation, Pr : TpM → TpM, which are defined inductively by

P0 = I, Pr = SrI − A ◦ Pr−1, r ≥ 1. The following formulas are useful in the proof (see, [Re], Lemma 2.1).

(2.1) trace(Pr) = (n − r)Sr,

(2.2) trace(A ◦ Pr) = (r + 1)Sr+1, 2 (2.3) trace(A ◦ Pr) = S1Sr+1 − (r + 2)Sr+2. From [AdCC] we have the second variation formula for hypersurfaces n+1 in a space form of constant curvature c, Qc , with constant 2-mean curvature:

2 d A1 R R 2 ∞ (2.4) |t=0= hP1(∇f),∇fidM− (S1S2−3S3+c(n−1)S1)f dM, ∀f∈C (D). dt2 D D c

Definition 2.1. When S2 = 0 and c = 0, M is stable if and only if Z Z 2 (2.5) hP1(∇f), ∇fidM ≥ −3 S3f dM, M M ∞ for any f ∈ Cc (M). One can see that if P1 ≡ 0, then S3 = 0 and M is stable. When S2 = const. 6= 0, M is stable if and only if Z Z 2 hP1(∇f), ∇fidM ≥ (S1S2 − 3S3 + c(n − 1)S1)f dM, D D ∞ R for all f ∈ Cc (M) and M fdM = 0. We say that M is strongly stable ∞ if and only if the above inequality holds for all f ∈ Cc (M). Similar to minimal hypersurface we can also define the index I for hy- persurfaces with constant scalar curvature. Given a relatively compact domain Ω ⊂ M, we denote by Ind 1(Ω) the number of linearly indepen- dent normal deformations with support on Ω that decrease A1. The index of the immersion are defined as 1 1 (2.6) Ind (M) := sup{Ind (Ω) Ω ⊂ M, Ωrelatively compact}. M is strongly stable if Ind 1(M) = 0. The following result has been known in [El]. Stable hypersurfaces with constant scalar curvature 5

n n+1 Lemma 2.1. Let M → Qc be a noncompact hypersurface with S2 = const. > 0. If M has finite index then there exist a compact set K ⊂ M such that M \ K is strongly stable. For hypersurfaces with constant mean curvature, do Carmo and Zhou [dCZ] proved that n+1 Theorem 2.1. Let x : M n → M be an isometric immersion with constant mean curvature H. Assume M has subexponential volume growth and finite index. Then there exist a constant R0 such that H ≤ −Ric (N), M\BR0 where N is a smooth normal vector field along M and Ric(N) is the Ricci curvature of M in the normal vector N. The technique in [dCZ] was generalized by Elbert [El] to prove the following result: Theorem 2.2. Let x : M n → Q(c)n+1 be an isometric immersion with 1 S2 = constant > 0. Assume that Ind M < ∞ and that the 1-volume of M is infinite and has polynomial growth. Then c is negative and

S2 ≤ −c. In particular, it implies that when c = 0 the hypersurfaces in the above theorem must have nonpositive scalar curvature.

3. Proof of the theorems 2 2 When S2 = 0 we know that |S1| = |A| . Thus, if S3 6= 0, we have 2 that |A| > 0. Hence S1 6= 0 and we can choose an orientation such that P1 is semi-positive definite. Since p 2 2 | P1A| = trace(A ◦ P1)

= −3S3, then, when c = 0, M is stable if Z Z p 2 2 (3.1) hP1(∇f), ∇fidM ≥ | P1A| f dM, M M ∞ for any f ∈ Cc (M). When S2 = 0, we have that the folowing inequality which is essentially due to Cheng and Yau[CY](see also Lemma 4.1 in [AdCC] or Lemma 3.2 in [Li]). 2 2 (3.2) |∇A| − |∇S1| ≥ 0. 6 Hil´arioAlencar, Walcy Santos and Detang Zhou

In the following lemma, we characterize the equality case in some special case. Lemma 3.1. Let M n(n ≥ 3) be a non-flat connected immersed 1- n+1 2 2 minimal hypersurface in R . If |∇A| = |∇S1| holds on all non- vanishing point of |A| in M, then each component of M with |A|= 6 0 must be a cylinder over a curve. Proof. To prove our lemma we recall here the computations in [SSY]. Choose a frame at p so that the second fundamental form is diagonalized, 2 P 2 we have |A| = i hii, and (3.3)   X 2 2 X 2 X 2 X X 2 hijk − |∇|A|| = ( hij)( hstk) − ( hijhijk)  i,j,k i,j s,t,k k i,j

−1 P 2  i,j hij

1 X = (h h − h h )2|A|−2 2 ij stk st ijk i,j,k,s,t  1 X 2 X 2 = 2  (hiihstk − hsthiik) + hss i,k,s,t s

  X X 2 −2  hijk |A| k i6=j

  1 X 2 −2 X 2 = 2  (hiihssk − hsshiik)  |A| + 2 hiij i,k,s i6=j

X 2 + hijk. i6=j,j6=k,i6=k The right hand side of above equation is nonnegative and is zero if and only if all terms on the right hand side of the last equation are zero. n+1 Suppose x : M → R is the 1-minimal immersion. Since M is not a hyperplane, then |A| is a nonnegative continuous function which does Stable hypersurfaces with constant scalar curvature 7 not vanish identically. Let p be such a point such that |A|(p) > 0. Then |A| > 0 in a connected open set U containing p. The equality in (3.2) implies

hjji = 0, for all j 6= i,

hijk = 0, for all j 6= i, j 6= k, k 6= i

hiihssk = hsshiik, for all i, s, k.

So we have hjij = 0, for all j 6= i, and from the last equation we claim that at most one i such that hiii 6= 0. Otherwise, without the loss of generality we assume h111 6= 0, and h222 6= 0, we have h11h22k = h22h11k for all k. This implies h11 = h22 = 0 by choosing k = 1, 2. Using again the third formula we have hjjh111 = h11hjj1 for j = 3, ··· , n. Hence hjj = 0 for all j = 3, ··· , n, which contradicts to |A|= 6 0. We now assume h111 6= 0 by continuity we can also assume h11 6= 0. From the last equation of above equation, we have h11hss1 = hssh111 for s 6= 1. Hence hss = 0 for all s 6= 1. This implies that M is a cylinder over a curve. 

We are now ready to prove

Theorem 3.1. There is no complete noncompact stable hypersurfaces n+1 in R with S2 = 0 and S3 6= 0 satisfying

R 3 S1 lim BR = 0. R→+∞ R2

Proof. Assume for the sake of contradiction that there were such a hypersurface M. From Lemma 3.7 in [AdCC], we have

2 2 (3.4) L1S1 = |∇A| − |∇S1| + 3S1S3. 8 Hil´arioAlencar, Walcy Santos and Detang Zhou

∞ Since for any φ ∈ Cc (M),

Z Z hP1(∇(φS1)), ∇(φS1)idM = hP1((∇φ)S1 + φ∇S1), (∇φ)S1) M M

+φ∇S1idM Z 2 = hP1(∇φ), ∇φiS1 dM M Z +2 hP1(∇φ), ∇S1iφS1dM M Z 2 + φ hP1(∇S1), ∇S1idM, M Stable hypersurfaces with constant scalar curvature 9 then using (3.4) we have

Z Z 2 2 2 2 φ S1(|∇A| − |∇S1| )dM = (L1S1 − 3S1S3)φ S1dM M M Z 2 = − hP1(∇S1), ∇(φ S1)idM M Z 2 2 − 3S3φ S1 dM M Z 2 = − φ hP1(∇S1), ∇S1idM M Z −2 hP1(∇φ), ∇S1iφS1dM M Z 2 2 − 3S3φ S1 dM ZM = − hP1(∇(φS1)), ∇(φS1)idM M Z 2 + hP1(∇φ), ∇(φ)iS1 dM M Z 2 2 − 3S3φ S1 dM M Z 2 ≤ hP1(∇φ), ∇φiS1 dM M Z 2 3 ≤ (n − 1) |∇φ| S1 dM, M

∞ for any φ ∈ Cc (M). Here we have used the stability inequality (2.5) in the fifth line and use the following consequence of (2.1) in the last inequality:

2 (3.5) (n − 1)S1|∇φ| ≥ hP1(∇φ), ∇φi. 10 Hil´arioAlencar, Walcy Santos and Detang Zhou

We can choose φ as  2R−r(x)  R , on B2R \ BR; φ(x) = 1, on BR;  0, on M \ B2R. 2 2 Thus from the choice of φ we have S1(|∇A| − |∇S1| ) ≡ 0. Therefore the elipticity of L1 implies L1S1 = 3S1S3. From Lemma 3.1, M must be a cylinder over a curve which contradicts S 6= 0. The proof is complete. 3  The following Lemma is of some independent interest and we include here since its second part is useful in the proof of Theorem 3.2.

n+1 Lemma 3.2. Let M be a complete immersed hypersurface in Qc with n(n−1) positive constant scalar curvature S2 > − 2 c and S1 6= 0. 1)If M is strongly stable outside a compact subset, then either M has finite 1-volume, or 1 Z lim S1 = +∞. R→+∞ 2 R BR 2)If M is strongly stable, then 1 Z lim S1 = +∞. R→+∞ 2 R BR In particular M has infinite 1-volume.

Proof. We can assume that there exists a geodesic ball BR0 ⊂ M such that M \ BR0 is strongly stable. That is, Z Z 2 (3.6) (S1S2 − 3S3 + c(n − 1)S1)f dM ≤ hP1(∇f), ∇fidM, M M ∞ for all f ∈ Cc (M \ BR0 ). Now, since S2 > 0, we have (see [AdCR], p. 392)

H1H2 ≥ H3, and 1/2 H1 ≥ H2 . n(n − 1) n(n − 1(n − 2) By using that S = nH , S = H and S = H , 1 1 2 2 2 3 6 3 it follows that (n − 2) S S ≥ 3S , n 1 2 3 Stable hypersurfaces with constant scalar curvature 11 that is, (n − 2) (3.7) − 3S ≥ − S S . 3 n 1 2 We also have that S  2S 1/2 1 ≥ 2 , n n(n − 1) which implies  2n 1/2 (3.8) S ≥ S1/2. 1 n − 1 2 By using inequality (3.7) in (3.6), it follows that Z   Z n − 2 2 S1S2 − S1S2 + c(n − 1)S1 f dM ≤ hP1(∇f), ∇fidM, M n M that is, Z   Z n(n − 1)c 2 n S2 + S1f dM ≤ hP1(∇f), ∇fidM. M 2 2 M By using (3.5), we obtain that Z Z 2 (n − 1) S1|∇f| dM ≥ hP1(∇f), ∇fidM M M Therefore, there exists a constant C > 0 such that Z Z 2 2 (3.9) S1|∇f| dM ≥ C S1f dM. M M

1) When M is strongly stable outside BR0 . We can choose f as  r(x) − R0, on BR +1 \ BR ;  0 0  1, on BR+R0+1 \ BR0+1; f(x) = 2R+R0+1−r(x)  R , on B2R+R0+1 \ BR+R0+1;  0, on M \ B2R+R0+1, where r(x) is the distance function to a fixed point. Then

1 Z Z Z S dM+ S dM ≥ C S dM. R2 1 1 1 B2R+R0+1\BR+R0+1 BR0+1\BR0 BR+R0+1\BR0+1 If the 1-volume is infinite, we can choose R large such that Z Z C S1dM > S1dM, BR+R0+1\BR0+1 BR0+1\BR0 12 Hil´arioAlencar, Walcy Santos and Detang Zhou hence 1 Z lim S1dM = +∞. R→+∞ R2 B2R+R0+1\BR+R0+1 2) When M is strongly stable we can choose a simpler test function f as  1, on B ;  R f(x) = 2R−r(x) R , on B2R \ BR;  0, on M \ B2R, which implies that when S1 6= 0, 1 Z lim S1dM = +∞. R→+∞ 2 R B2R The proof is complete.  Theorem 3.2. There is no complete immersed strongly stable hyper- n n+1 M → R , n ≥ 3, with positive constant scalar curvature and polynomial growth of 1-volume, that is R S1dM lim BR < ∞, R→∞ Rn n where BR is a geodesic ball of radius R of M . Proof. Suppose that M is a complete immersed strongly stable hy- n n+1 persurface M → R , n ≥ 3, with positive constant scalar curvature. R From Theorem 2.2, it suffices to show that the 1-volume M S1dM is infinite which is the part (2) of Lemma 3.2. 

4. Graphs with S2 = const in Euclidean space In this section we include some stability properties and estimates for n entire graphs on R which may be known to experts and not easy to find a reference. Using these facts we give the proof of Corollary 4.1. Let n n+1 n M a hypersurface of R given by a graph of a function u : R → R ∞ n of class C (R ). For such hypersurfaces we have: n n Proposition 4.1. Let M a graph of a function u : R → R of class ∞ n C (R ). Then n (1) If S2 = 0 and S1 does not change sign on M, then M is a stable hypersurface. n (2) If M has S2 = C > 0, then M is strongly stable. Stable hypersurfaces with constant scalar curvature 13

∞ Proof. Considerer and f : M → R a C function with compact p 2 support and let W = 1 + |∇u| . In order to calculate hP1(∇f), ∇fi, write g = fW . Thus g g hP (∇f), ∇fi = hP (∇( )), ∇( )i 1 1 W W 1 1 1 1 = hP (g∇ + ∇g ), g∇( ) + ∇gi 1 W W W W 1 1 1 1 = hgP (∇ ) + P (∇g), g∇( ) + ∇gi 1 W W 1 W W 1 1 g 1 = g2hP (∇ ), ∇ i + hP (∇ ), ∇gi 1 W W W 1 W g 1 1 + hP (∇g), ∇ i + hP (∇g), ∇gi. W 1 W W 2 1

By using that P1 is selfadjoint, we have: (4.1) 1 1 g 1 1 hP (∇f), ∇fi = g2hP (∇ ), ∇ i+2 hP (∇ ), ∇gi+ hP (∇g), ∇gi. 1 1 W W W 1 W W 2 1

On the other hand, if {e1, ..., en} is a geodesic frame along M,

n 1 X 1 div(fgP (∇ ) = h∇ (fgP (∇ )), e i 1 W ei 1 W i i=1

n X 1 1 1 = hfg P (∇ ) + f gP (∇ ) + fg∇ (P (∇ )), e i i 1 W i 1 W ei 1 W i i=1

n X  1 1 = fg hP (∇ ), e i + f ghP (∇ ), e i i 1 W i i 1 W i i=1

1  +fgh∇ (P (∇ )), e i . ei 1 W i

g Since f = , we get W

1  1  fi = gi + g , W W i 14 Hil´arioAlencar, Walcy Santos and Detang Zhou that is,   1 2 1 gfi = ggi + g W W i   2 1 = fgi + g W i Hence, n 1 X 1  1  1 1 div(fgP (∇ ) = {fg hP (∇ ), e i + (fg + g2 )hP (∇ ), e i} + fgL ( ) 1 W i 1 W i i W 1 W i 1 W i=1 i n X 1  1  1 1 = {2fg hP (∇ ), e i + g2 hP (∇ ), e i} + fgL ( ) i 1 W i W 1 W i 1 W i=1 i 1 1 1 1 = 2fhP (∇ ), ∇gi + g2hP (∇ ), ∇( )i + fgL ( ) 1 W 1 W W 1 W g 1 1 1 1 = 2 h∇ ,P (∇g)i + g2hP (∇ ), ∇( )i + f 2WL ( ). W W 1 1 W W 1 W Thus, (4.2) g 1 1 1 1 1 2 h∇ ,P (∇g)i = div(fgP (∇ ))−g2hP (∇ ), ∇( )i−f 2WL ( ). W W 1 1 W 1 W W 1 W Now, by using (4.2) into equation (4.1), we get 1 1 1 hP (∇f), ∇fi = div(fgP (∇ )) − f 2WL ( ) + hP (∇g), ∇gi. 1 1 W 1 W W 2 1 Now, the divergence theorem implies that Z Z Z 2 1 1 hP1(∇f), ∇fidM = − f WL1( )dM+ 2 hP1(∇g), ∇gidM. M M W M W 2 2 Choose the orientation of M in such way that S1 ≥ 0. Since S1 − |A| = 2 2S2 ≥ 0, we obtain that S1 ≥ |A|. Thus, hP1(∇g), ∇gi = S1|∇g| − 2 hA∇g, ∇gi ≥ (S1 − |A|)|∇g| ≥ 0, which implies that Z Z 2 1 (4.3) hP1(∇f), ∇fidM ≥ − f WL1( )dM. M M W

When S2 is constant, we will use the following formula proved by Reilly (see [Re], Proposition C). 1 1 L ( ) = L (hN, e i) = −(S S −3S )hN, e i = −(S S −3S ) , 1 W 1 n+1 1 2 3 n+1 1 2 3 W Stable hypersurfaces with constant scalar curvature 15 where N is the normal vector of M and en+1 = (0, ..., 0, ±1), according to our choice of the orientation of M. Thus, Z Z 2 hP1(∇f), ∇fidM ≥ (S1S2 − 3S3)f dM, M M for all function f with compact support. Hence M is stable if S2 = 0 and strongly stable in the case S 6= 0. 2 

Remark 4.1. We would like to remark that the operator L1 need not to be elliptic in the above proof.

n n Proposition 4.2. Let M a graph of a function u : R → R of class ∞ n C (R ), with S1 ≥ 0. Let BR be a geodesic ball of radius R in M. Then Z C(n) n S1dM ≤ R , BθR 1 − θ Z where C(n) and θ are constants, with 0 < θ < 1. In particular, S1dM M has polynomial growth.

∞ Proof. Let f : M → R be a be a function in C0 (M), that is a smooth function with compact support. Observe that  ∇u ∇u  ∇u div f = fdiv + ∇f, , W W W ∇u where W = p1 + |∇u|2. By using the fact that S is given by S = div , 1 1 W we have that

Z Z ∇u Z  ∇u (4.4) fS1dM = fdiv dM = − ∇f, dM. M M W M W

Now, choose a family of geodesic balls BR that exhausts M. Fix θ, with 0 < θ < 1 and let f : M → R be a continuous function that is one on BθR, zero outside BR and linear on BR \ BθR. Therefore, from equation (4.4) we obtain Z Z Z   ∇u S1dM ≤ fS1dM ≤ , ∇f dM. BθR BR BR W 16 Hil´arioAlencar, Walcy Santos and Detang Zhou

|∇u| By using Cauchy-Schwarz inequality and the fact that ≤ 1, it W follows that Z Z Z 1 1 S1dM ≤ |∇f|dM ≤ dM ≤ vol(BR). BθR BR Br\BθR (1 − θ)R (1 − θ)R n+1 We observe that since M is a graph, if ΩR = {(x1, .., xn+1) ∈ R |−R ≤ p 2 2 xn+1 ≤ R; x1 + ... + xn ≤ R}, then Z n+1 vol(BR) ≤ 1dx1...dxn+1 = C(n)R . ΩR Hence, Z 1 C(n) n S1dM ≤ vol(BR) = R . BθR (1 − θ)R 1 − θ  We have the following Corollary of Theorem 3.2 n Corollary 4.1. Any entire graph on R with nonnegative constant scalar curvature must have zero scalar curvature. Proof. Suppose by sake of contradiction that there exist a entire graph with S2 = const > 0. Such graph is strongly stable and if S2 > 0, 2 2 we get that S1 = |A| + 2S2 > 0, we obtain that S1 does not change sign and we can choose the orientation in such way that S1 > 0. Thus the graph has polynomial growth of the 1-volume. Thus we have a con- tradiction with Theorem 3.2. Thus it follows that S2 = 0.  References [AdCC] Alencar, H., do Carmo, M., Colares, A.G. - Stable hypersurfaces with constant scalar curvature, Math. Z. 213 (1993), 117–131. [AdCE] Alencar, H., do Carmo, M., Elbert, M.F. - Stablity of hypersurfaces with vanishing r-constant curvatures in euclidean spaces, J. Reine Angew. Math. 554 (2003), 201–216. [AdCR] Alencar, H., do Carmo, M., Rosenberg, H. - On the first eigenvalue of the linearized operator of the rth mean curvature of a hypersurface. Annals of Global Analysis and Geometry 11, no. 4 (1993), 387–395. [ASZ] Alencar, H., Santos, W., Zhou, D. - Curvature integral estimates for complete hypersurfaces, arXiv:0903.2035. [Che] Cheng, X.- On constant mean curvature hypersurfeces with finite index, Arch. Math. 86 (2006), 365–374. [CY] Cheng, S.Y., Yau, S.T.- Hypersurfaces with constant scalar curvature, Math. Ann. 225 (1977), 195–204. Stable hypersurfaces with constant scalar curvature 17

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Hil´arioAlencar Universidade Federal de Alagoas, Instituto de Matem´atica,57072-900, Macei´o-AL, Brazil. Email: [email protected]

Detang Zhou Universidade Federal Fluminense, Instituto de Matem´atica,24020-140, Niter´oi-RJ, Brazil. Email: [email protected]

Walcy Santos Universidade Federal do Rio de Janeiro, Instituto de Matem´atica, 21941-909, Rio de Janeiro-RJ, Brazil. Email: [email protected]