Mgf 1107, Spring 2016 Practice Questions for Exam #1 1

Total Page：16

File Type：pdf, Size：1020Kb

MGF 1107, SPRING 2016 PRACTICE QUESTIONS FOR EXAM #1 1. Perform the following number base conversions: (24)10 to base 2 (10010011)2 to base 16 (3A4)16 to base 10 2. Identify each of the following numbers as prime, semi-prime, or composite. (Semi- primes are products of exactly two prime numbers. e.g., 85 = 5 x 17.) 30 445 23 33 101 3. Find the unique prime factorization for each of the following numbers: 57 440 153 242 3025 98 4. Which of the following is true about the number (212 – 1)? (a) it is prime (b) it is composite (c) it is neither prime nor composite (d) it is both prime and composite 5. Euler’s formula fails for n = 41. Why? 6. Verify that Escott’s formula yields a prime number for n = 30. 7. Verify that 28 is a perfect number. 8. Identify each of the following numbers as perfect, deficient, or abundant: 16 38 18 9. Express each of the following as the sum of two prime numbers: 14 10 22 38 10. Find three ways to express 36 as the sum of two prime numbers. 11. One of Fermat’s theorems is that an odd prime number can be expressed as the difference of two perfect squares in one and only one way. Express the number 13 as the difference of two perfect squares. 12. Find the Greatest Common Divisor of the following pairs of numbers: 48 and 80 22, 66, and 242 198 and 1287 13. Find the Least Common Multiple of the following pairs of numbers: 34 and 6 60 and 105 340 and 782 14. Find the fifth Fibonacci number. 15. Find the tenth Fibonacci number. 16. What is the relationship between the Fibonacci sequence and the Golden Ratio? BONUS QUESTION: A palindrome is a word or number that is the same when the characters are arranged forward or backward. Examples are “radar” and 58085. Which palindromic between 100 and 200 are also prime? .

Copy Link

Recommended publications

1 Mersenne Primes and Perfect Numbers
1 Mersenne Primes and Perfect Numbers Basic idea: try to construct primes of the form an − 1; a, n ≥ 1. e.g., 21 − 1 = 3 but 24 − 1=3· 5 23 − 1=7 25 − 1=31 26 − 1=63=32 · 7 27 − 1 = 127 211 − 1 = 2047 = (23)(89) 213 − 1 = 8191 Lemma: xn − 1=(x − 1)(xn−1 + xn−2 + ···+ x +1) Corollary:(x − 1)|(xn − 1) So for an − 1tobeprime,weneeda =2. Moreover, if n = md, we can apply the lemma with x = ad.Then (ad − 1)|(an − 1) So we get the following Lemma If an − 1 is a prime, then a =2andn is prime. Definition:AMersenne prime is a prime of the form q =2p − 1,pprime. Question: are they infinitely many Mersenne primes? Best known: The 37th Mersenne prime q is associated to p = 3021377, and this was done in 1998. One expects that p = 6972593 will give the next Mersenne prime; this is close to being proved, but not all the details have been checked. Definition: A positive integer n is perfect iff it equals the sum of all its (positive) divisors <n. Definition: σ(n)= d|n d (divisor function) So u is perfect if n = σ(u) − n, i.e. if σ(u)=2n. Well known example: n =6=1+2+3 Properties of σ: 1. σ(1) = 1 1 2. n is a prime iff σ(n)=n +1 p σ pj p ··· pj pj+1−1 3. If is a prime, ( )=1+ + + = p−1 4. (Exercise) If (n1,n2)=1thenσ(n1)σ(n2)=σ(n1n2) “multiplicativity”.
[Show full text]
Prime Divisors in the Rationality Condition for Odd Perfect Numbers
Aid#59330/Preprints/2019-09-10/www.mathjobs.org RFSC 04-01 Revised The Prime Divisors in the Rationality Condition for Odd Perfect Numbers Simon Davis Research Foundation of Southern California 8861 Villa La Jolla Drive #13595 La Jolla, CA 92037 Abstract. It is sufficient to prove that there is an excess of prime factors in the product of repunits with odd prime bases defined by the sum of divisors of the integer N = (4k + 4m+1 ℓ 2αi 1) i=1 qi to establish that there do not exist any odd integers with equality (4k+1)4m+2−1 between σ(N) and 2N. The existence of distinct prime divisors in the repunits 4k , 2α +1 Q q i −1 i , i = 1,...,ℓ, in σ(N) follows from a theorem on the primitive divisors of the Lucas qi−1 sequences and the square root of the product of 2(4k + 1), and the sequence of repunits will not be rational unless the primes are matched. Minimization of the number of prime divisors in σ(N) yields an infinite set of repunits of increasing magnitude or prime equations with no integer solutions. MSC: 11D61, 11K65 Keywords: prime divisors, rationality condition 1. Introduction While even perfect numbers were known to be given by 2p−1(2p − 1), for 2p − 1 prime, the universality of this result led to the the problem of characterizing any other possible types of perfect numbers. It was suggested initially by Descartes that it was not likely that odd integers could be perfect numbers [13]. After the work of de Bessy [3], Euler proved σ(N) that the condition = 2, where σ(N) = d|N d is the sum-of-divisors function, N d integer 4m+1 2α1 2αℓ restricted odd integers to have the form (4kP+ 1) q1 ...qℓ , with 4k + 1, q1,...,qℓ prime [18], and further, that there might exist no set of prime bases such that the perfect number condition was satisfied.
[Show full text]
On Perfect and Multiply Perfect Numbers
On perfect and multiply perfect numbers . by P. ERDÖS, (in Haifa . Israel) . Summary. - Denote by P(x) the number o f integers n ~_ x satisfying o(n) -- 0 (mod n.), and by P2 (x) the number of integers nix satisfying o(n)-2n . The author proves that P(x) < x'314:4- and P2 (x) < x(t-c)P for a certain c > 0 . Denote by a(n) the sum of the divisors of n, a(n) - E d. A number n din is said to be perfect if a(n) =2n, and it is said to be multiply perfect if o(n) - kn for some integer k . Perfect numbers have been studied since antiquity. l t is contained in the books of EUCLID that every number of the form 2P- ' ( 2P - 1) where both p and 2P - 1 are primes is perfect . EULER (1) proved that every even perfect number is of the above form . It is not known if there are infinitely many even perfect numbers since it is not known if there are infinitely many primes of the form 2P - 1. Recently the electronic computer of the Institute for Numerical Analysis the S .W.A .C . determined all primes of the form 20 - 1 for p < 2300. The largest prime found was 2J9 "' - 1, which is the largest prime known at present . It is not known if there are an odd perfect numbers . EULER (') proved that all odd perfect numbers are of the form (1) pam2, p - x - 1 (mod 4), and SYLVESTER (') showed that an odd perfect number must have at least five distinct prime factors .
[Show full text]
ON PERFECT and NEAR-PERFECT NUMBERS 1. Introduction a Perfect
ON PERFECT AND NEAR-PERFECT NUMBERS PAUL POLLACK AND VLADIMIR SHEVELEV Abstract. We call n a near-perfect number if n is the sum of all of its proper divisors, except for one of them, which we term the redundant divisor. For example, the representation 12 = 1 + 2 + 3 + 6 shows that 12 is near-perfect with redundant divisor 4. Near-perfect numbers are thus a very special class of pseudoperfect numbers, as defined by Sierpiński. We discuss some rules for generating near-perfect numbers similar to Euclid's rule for constructing even perfect numbers, and we obtain an upper bound of x5=6+o(1) for the number of near-perfect numbers in [1; x], as x ! 1. 1. Introduction A perfect number is a positive integer equal to the sum of its proper positive divisors. Let σ(n) denote the sum of all of the positive divisors of n. Then n is a perfect number if and only if σ(n) − n = n, that is, σ(n) = 2n. The first four perfect numbers { 6, 28, 496, and 8128 { were known to Euclid, who also succeeded in establishing the following general rule: Theorem A (Euclid). If p is a prime number for which 2p − 1 is also prime, then n = 2p−1(2p − 1) is a perfect number. It is interesting that 2000 years passed before the next important result in the theory of perfect numbers. In 1747, Euler showed that every even perfect number arises from an application of Euclid's rule: Theorem B (Euler). All even perfect numbers have the form 2p−1(2p − 1), where p and 2p − 1 are primes.
[Show full text]
+P.+1 P? '" PT Hence
1907.] MULTIPLY PEKFECT NUMBERS. 383 A TABLE OF MULTIPLY PERFECT NUMBERS. BY PEOFESSOR R. D. CARMICHAEL. (Read before the American Mathematical Society, February 23, 1907.) A MULTIPLY perfect number is one which is an exact divisor of the sum of all its divisors, the quotient being the multiplicity.* The object of this paper is to exhibit a method for determining all such numbers up to 1,000,000,000 and to give a complete table of them. I include an additional table giving such other numbers as are known to me to be multiply perfect. Let the number N, of multiplicity m (m> 1), be of the form where pv p2, • • •, pn are different primes. Then by definition and by the formula for the sum of the factors of a number, we have +P? -1+---+p + ~L pi" + Pi»'1 + • • (l)m=^- 1 •+P.+1 p? '" PT Hence (2) Pi~l Pa"1 Pn-1 These formulas will be of frequent use throughout the paper. Since 2•3•5•7•11•13•17•19•23 = 223,092,870, multiply perfect numbers less than 1,000,000,000 contain not more than nine different prime factors ; such numbers, lacking the factor 2, contain not more than eight different primes ; and, lacking the factors 2 and 3, they contain not more than seven different primes. First consider the case in which N does not contain either 2 or 3 as a factor. By equation (2) we have (^\ «M ^ 6 . 7 . 11 . 1£. 11 . 19 .2ft « 676089 [Ö) m<ï*6 TTT if 16 ï¥ ïî — -BTÏTT6- Hence m=2 ; moreover seven primes are necessary to this value.
[Show full text]
Some New Results on Odd Perfect Numbers
Pacific Journal of Mathematics SOME NEW RESULTS ON ODD PERFECT NUMBERS G. G. DANDAPAT,JOHN L. HUNSUCKER AND CARL POMERANCE Vol. 57, No. 2 February 1975 PACIFIC JOURNAL OF MATHEMATICS Vol. 57, No. 2, 1975 SOME NEW RESULTS ON ODD PERFECT NUMBERS G. G. DANDAPAT, J. L. HUNSUCKER AND CARL POMERANCE If ra is a multiply perfect number (σ(m) = tm for some integer ί), we ask if there is a prime p with m = pan, (pa, n) = 1, σ(n) = pα, and σ(pa) = tn. We prove that the only multiply perfect numbers with this property are the even perfect numbers and 672. Hence we settle a problem raised by Suryanarayana who asked if odd perfect numbers neces- sarily had such a prime factor. The methods of the proof allow us also to say something about odd solutions to the equation σ(σ(n)) ~ 2n. 1* Introduction* In this paper we answer a question on odd perfect numbers posed by Suryanarayana [17]. It is known that if m is an odd perfect number, then m = pak2 where p is a prime, p Jf k, and p = a z= 1 (mod 4). Suryanarayana asked if it necessarily followed that (1) σ(k2) = pa , σ(pa) = 2k2 . Here, σ is the sum of the divisors function. We answer this question in the negative by showing that no odd perfect number satisfies (1). We actually consider a more general question. If m is multiply perfect (σ(m) = tm for some integer t), we say m has property S if there is a prime p with m = pan, (pa, n) = 1, and the equations (2) σ(n) = pa , σ(pa) = tn hold.
[Show full text]
SUPERHARMONIC NUMBERS 1. Introduction If the Harmonic Mean Of
MATHEMATICS OF COMPUTATION Volume 78, Number 265, January 2009, Pages 421–429 S 0025-5718(08)02147-9 Article electronically published on September 5, 2008 SUPERHARMONIC NUMBERS GRAEME L. COHEN Abstract. Let τ(n) denote the number of positive divisors of a natural num- ber n>1andletσ(n)denotetheirsum.Thenn is superharmonic if σ(n) | nkτ(n) for some positive integer k. We deduce numerous properties of superharmonic numbers and show in particular that the set of all superhar- monic numbers is the first nontrivial example that has been given of an infinite set that contains all perfect numbers but for which it is difficult to determine whether there is an odd member. 1. Introduction If the harmonic mean of the positive divisors of a natural number n>1isan integer, then n is said to be harmonic.Equivalently,n is harmonic if σ(n) | nτ(n), where τ(n)andσ(n) denote the number of positive divisors of n and their sum, respectively. Harmonic numbers were introduced by Ore [8], and named (some 15 years later) by Pomerance [9]. Harmonic numbers are of interest in the investigation of perfect numbers (num- bers n for which σ(n)=2n), since all perfect numbers are easily shown to be harmonic. All known harmonic numbers are even. If it could be shown that there are no odd harmonic numbers, then this would solve perhaps the most longstand- ing problem in mathematics: whether or not there exists an odd perfect number. Recent articles in this area include those by Cohen and Deng [3] and Goto and Shibata [5].
[Show full text]
Comprehension Task 3: Deficient, Perfect and Abundant Numbers
Comprehension Task 3: Deficient, Perfect and Abundant Numbers Deficient, Perfect and Abundant Numbers The ideas explored in this article are ideas that were explored by the Ancient Greeks over 2000 years ago, and have been studied further since, notably in the 1600s and 1800s. They may, perhaps, be pretty useless ideas for the world, but are quite fun, and despite leading mathematicians playing with the ideas, mysteries remain, as I shall explain. Some numbers, like 12, have many factors. (A factor of a number is a number that allows exact division. For example, 3 is a factor of 12, because there exists a whole number that fills the gap in this number sentence: 3 ×◻= 12.) Some numbers, like 13, are prime and have just two. (In fact there are infinitely many of these prime numbers; that’s another story for another day). (A prime number is a number with exactly two factors. For example, 13 is prime, because it has exactly two factors, 1 and 13.) We can get a sense of how ‘well-endowed’ a number is with factors, taking into account its size (after all, bigger numbers have a higher chance of having factors, in some sense, than smaller numbers), by considering the sum of all its factors less than itself, and comparing this ‘factor sum’ to the number itself. For example, consider the number 14. Its factors are 1, 2, 7, 14. If we add together all the factors lower than 14 itself, we get 1 + 2 + 7 = 10. This is less than 14, so we say that 14 is deficient.
[Show full text]
Introduction to Abstract Algebra “Rings First”
Introduction to Abstract Algebra \Rings First" Bruno Benedetti University of Miami January 2020 Abstract The main purpose of these notes is to understand what Z; Q; R; C are, as well as their polynomial rings. Contents 0 Preliminaries 4 0.1 Injective and Surjective Functions..........................4 0.2 Natural numbers, induction, and Euclid's theorem.................6 0.3 The Euclidean Algorithm and Diophantine Equations............... 12 0.4 From Z and Q to R: The need for geometry..................... 18 0.5 Modular Arithmetics and Divisibility Criteria.................... 23 0.6 *Fermat's little theorem and decimal representation................ 28 0.7 Exercises........................................ 31 1 C-Rings, Fields and Domains 33 1.1 Invertible elements and Fields............................. 34 1.2 Zerodivisors and Domains............................... 36 1.3 Nilpotent elements and reduced C-rings....................... 39 1.4 *Gaussian Integers................................... 39 1.5 Exercises........................................ 41 2 Polynomials 43 2.1 Degree of a polynomial................................. 44 2.2 Euclidean division................................... 46 2.3 Complex conjugation.................................. 50 2.4 Symmetric Polynomials................................ 52 2.5 Exercises........................................ 56 3 Subrings, Homomorphisms, Ideals 57 3.1 Subrings......................................... 57 3.2 Homomorphisms.................................... 58 3.3 Ideals.........................................
[Show full text]
Arxiv:1606.08690V5 [Math.NT] 27 Apr 2021 on Prime Factors of Mersenne
On prime factors of Mersenne numbers Ady Cambraia Jr,∗ Michael P. Knapp,† Ab´ılio Lemos∗, B. K. Moriya∗ and Paulo H. A. Rodrigues‡ [email protected] [email protected] [email protected] [email protected] paulo [email protected] April 29, 2021 Abstract n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1. Let ω(n) be the number of distinct prime divisors of n. In this short note, we present a description of the Mersenne numbers satisfying ω(Mn) ≤ 3. Moreover, we prove that the inequality, (1−ǫ) log log n given ǫ> 0, ω(Mn) > 2 − 3 holds for almost all positive integers n. Besides, a we present the integer solutions (m, n, a) of the equation Mm+Mn = 2p with m,n ≥ 2, p an odd prime number and a a positive integer. 2010 Mathematics Subject Classification: 11A99, 11K65, 11A41. Keywords: Mersenne numbers, arithmetic functions, prime divisors. 1 Introduction arXiv:1606.08690v5 [math.NT] 27 Apr 2021 n Let (Mn)n≥0 be the Mersenne sequence defined by Mn = 2 − 1, for n ≥ 0. A simple argument shows that if Mn is a prime number, then n is a prime number. When Mn is a prime number, it is called a Mersenne prime. Throughout history, many researchers sought to find Mersenne primes. Some tools are very important for the search for Mersenne primes, mainly the Lucas-Lehmer test. There are papers (see for example [1, 5, 21]) that seek to describe the prime factors of Mn, where Mn is a composite number and n is a prime number.
[Show full text]
Primitive Indexes, Zsigmondy Numbers, and Primoverization
Primitive Indexes, Zsigmondy Numbers, and Primoverization Tejas R. Rao September 22, 2018 Abstract. We define a primitive index of an integer in a sequence to be the index of the term with the integer as a primitive divisor. For the sequences ku + hu and ku − hu, we discern a formula to find the primitive indexes of any composite number given the primitive indexes of its prime factors. We show how this formula reduces to a formula relating the multiplicative order of k modulo N to that of its prime factors. We then introduce immediate consequences of the formula: certain sequences which yield the same primitive indexes for numbers with the same n n unique prime factors, an expansion of the lifting the exponent lemma for ν2(k + h ), a simple formula to find any Zsigmondy number, a note on a certain class of pseudoprimes titled overpseudoprime, and a proof that numbers such as Wagstaff numbers are either overpseudoprime or prime. 1 The Formula A primitive index of a number is the index of the term in a sequence that has that number as a primitive divisor. Let k and h be positive integers for the duration of this paper. We u u u u N denote the primitive index of N in k − h as PN (k, h). For k + h , it is denoted P (k, h). Note that PN (k, 1) = ON (k), where ON (k) refers to the multiplicative order of k modulo N. Both are defined as the first positive integer m such that km ≡ 1 mod N.
[Show full text]
Prime and Perfect Numbers
Chapter 34 Prime and perfect numbers 34.1 Infinitude of prime numbers 34.1.1 Euclid’s proof If there were only finitely many primes: 2, 3, 5, 7, ...,P, and no more, consider the number Q = (2 3 5 P ) + 1. · · ··· Clearly it is divisible by any of the primes 2, 3,..., P , it must be itself a prime, or be divisible by some prime not in the list. This contradicts the assumption that all primes are among 2, 3, 5,..., P . 34.1.2 Fermat numbers 2n The Fermat numbers are Fn := 2 + 1. Note that 2n 2n−1 2n−1 Fn 2 = 2 1= 2 + 1 2 1 = Fn 1(Fn 1 2). − − − − − − By induction, Fn = Fn 1Fn 2 F1 F0 + 2, n 1. − − ··· · ≥ From this, we see that Fn does not contain any factor of F0, F1, ..., Fn 1. Hence, the Fermat numbers are pairwise relatively prime. From this,− it follows that there are infinitely primes. 1 1 It is well known that Fermat’s conjecture of the primality of Fn is wrong. While F0 = 3, F1 = 5, 32 F2 = 17, F3 = 257, and F4 = 65537 are primes, Euler found that F5 = 2 + 1 = 4294967297 = 641 6700417. × 1202 Prime and perfect numbers 34.2 The prime numbers below 20000 The first 2262 prime numbers: 10 20 30 40 50 60 70 80 90 100 bbbbbb bb bbb b bb bb b bb b bb bb bb b b b b bb b b b b b b b b b b b b b b b bb b b b b b b b b b b b b b b b b bb b b b b bb b b b b b bb b b b b b b b b b b b b b b b b b b bb b b b b b b b b bb b b b bb b b b b b b b b b b b b bb b b b b b b b b b bb b b b b b b b b b b b b b b b b b b bb b b bb b b b b bb b b b b b b b b b b b b b 100 b b bb b bb b bb b b b b bb b b b b b bb b b b b b b b bb b bb b b b b b bb b b b
[Show full text]