<<

LA-04: Triangular Systems Goal: To learn how to efficiently solve triangular linear systems.

Solving Triangular Systems A triangular has zeros either above the , or below the diagonal.

Triangular matrices occur in certain matrix , and are a useful type of matrix.

Solving Upper-Triangular Systems: Back Substitution

Start with the last row

Now it's easy to solve for in the second-last row.

Linear Algebra Page 16 The i-th row…

Back Substitution Algorithm (a.k.a. Back Solve) (see page 101 in the course notes)

Complexity For each , the -loop performs flops (floating-point operations). Together with

Sum over

Linear Algebra Page 17 Forward Substitution

Linear Algebra Page 18 To solve a system of linear equations

one can use Gaussian elimination. 1) Form the .

2) Perform linear row operations to get an upper- form

3) You might have been taught to follow this with more row operations to get a .

A better way is to use back substitution after step 2. Solve

Linear Algebra Page 19 LA-05: Gaussian Elimination Goal: To review how row operations can be used to reduce and solve a linear system.

LU Any can be factored into a product of an upper- triangular and lower-triangular matrices such that

is a used to swap rows. LU factorization is essentially the same as Gaussian elimination.

In this case, there is no way to use the pivot element to get rid of the 5. So, swap rows 2 and 3.

We will go over the details later, but for now I'll simply state that LU factorization takes flops.

Applications of LU Factorization a) Solving

Linear Algebra Page 20 Two steps to compute 1) Solve 2) Solve

Gaussian elimination = LU factorization + forward sub + back sub b) Solving Suppose and each have columns.

1) Factor: 2) Solve:

Take-home message: Do the expensive LU factorization once, and use it for each of the systems.

Gaussian Elimination (GE)

Linear Algebra Page 21 In matrix form:

For general , the big picture of GE…

GE Version 1: for i = 1:N-1 eliminate xi from rows i+1 to N end

At the i-th stage of GE…

Linear Algebra Page 22 GE Version 2: for i = 1:N-1 for k = i+1:N

mult = aki/aii row(k) = row(k) - mult*row(i)

end end

To update the entire row

for j = i+1:N

akj = akj - mult*aij end

Final GE Algorithm: for i = 1:N-1

for k = i+1:N mult = aki/aii

Linear Algebra Page 23 mult = aki/aii for j = i+1:N akj = akj - mult*aij end aki = 0 end

end

Notes: 1) The lower-triangular part is all 0. 2) We may use those elements to store the multipliers.

Linear Algebra Page 24 LA-06: LU Factorization Goal: To find out how to compute LU factorization.

LU Factorization Algorithm Consider the first step of GE,

Matrix interpretation: row operations

In general, at the k-th step… where

Linear Algebra Page 25 The effect of left-multiplying by is to eliminate from rows to . At the final step: Recall that

Amazing Facts 1) If and are lower- and unit diagonal, then 2) If is lower- and unit diagonal, then

Linear Algebra Page 26 Theorem:

Properties of . 1)

2)

Linear Algebra Page 27 Linear Algebra Page 28 LA-07: Pivoting Goal: To stabilize LU factorization using row pivoting.

Stability of LU Factorization In LU factorization, a problem arises when we have:

(1) a zero pivot

(2)

Pivoting

Find

Swap rows and , and continue. Note:

As mentioned earlier, these row-swapping operations can be Linear Algebra Page 29 As mentioned earlier, these row-swapping operations can be represented by matrix multiplication by a permutation matrix, eg. to swap rows & , simply swap rows & in the .

Let's put it all together.

Linear Algebra Page 30 Linear Algebra Page 31 Linear Algebra Page 32 Linear Algebra Page 33