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PARTIAL BALAYAGE and the EXTERIOR INVERSE PROBLEM of POTENTIAL THEORY 1. Introduction Let B Be an Open Ball in Euclidean Space R

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PARTIAL BALAYAGE and the EXTERIOR INVERSE PROBLEM of POTENTIAL THEORY 1. Introduction Let B Be an Open Ball in Euclidean Space R PARTIAL BALAYAGE AND THE EXTERIOR INVERSE PROBLEM OF POTENTIAL THEORY STEPHEN J GARDINER AND TOMAS SJODIN¨ 1. Introduction Let B be an open ball in Euclidean space RN (N ≥ 2) and let σ∗ denote nor- malised surface area measure on @B. For any function h that is harmonic on a neighbourhood of B we have the spherical mean value property Z ∗ (1) h(x0) = hdσ ; @B where x0 denotes the centre of B. Let − log jx − yj (N = 2) U (y) = x jx − yj2−N (N ≥ 3) R and (for a suitable measure µ) Uµ(x) = Uxdµ. Using (1) with h = Ux (x 2 N ∗ R nB), we obtain the familiar fact that Uδx0 = Uσ outside B, where δx0 is the ∗ Dirac measure at x0. In this context we regard σ as the result of sweeping δx0 out of B. N ∗ Now let λ denote Lebesgue measure on R and let λ = (λ jB ) /λ(B). For any integrable harmonic function h on B we have the volume mean value property R ∗ ∗ h(x0) = B hdλ and, arguing as before, this yields Uδx0 = Uλ outside B. By analogy with the previous paragraph we can regard λ∗ as the result of a \partial sweeping" (or partial balayage) of δx0 , in which a certain density of measure is allowed to remain. Such a notion has been developed by Gustafsson and Sakai (see, for example, [8]) in connection with the construction of certain types of quadrature domains for harmonic functions. To be more specific, let µ be a measure with compact support, and suppose we have a procedure for arriving at a bounded open set Ω containing the support of µ such that Uµ = U(λ jΩ ) outside Ω. (Not every measure µ will have such an associated set Ω.) Arranging, by the addition to Ω of a null set if necessary, that the Lebesgue points of RN nΩ are dense in RN nΩ, it follows that rUµ = rU(λ jΩ ) outside Ω. Thus Z Z N hdλ = hdµ whenever h 2 fUx;@iUx : x 2 R nΩ; i = 1; :::; Ng: Ω R R An approximation result of Sakai [11] now shows that Ω hdλ = hdµ for every λ-integrable harmonic function h on Ω; that is, Ω is a quadrature domain with respect to the measure µ. 02000 Mathematics Subject Classification: 31B20. This research was supported by Science Foundation Ireland under Grant 06/RFP/MAT057, and is also part of the programme of the ESF Network \Harmonic and Complex Analysis and Applications" (HCAA). 1 2 STEPHEN J GARDINER AND TOMAS SJODIN¨ Partial balayage is closely related to the obstacle problem, and to the abstract theory of potential cones (see, for example, [2]). However, in this article, we will not rely on these connections. Instead we will present a concise, self-contained exposition of partial balayage from the viewpoint of classical potential theory. Along the way we will obtain a new proof of the singularity of harmonic measure with respect to Lebesgue measure and a general version of the Hele-Shaw law for fluid flow. The paper concludes with an outline of how partial balayage has recently been employed to make progress on the exterior inverse problem of potential theory [6]. 2. Partial reductions of superharmonic functions Now let Ω ⊆ RN be an open set that possesses a Green function (that is, Ω must have nonpolar complement in the case where N = 2). Further, let u and v be superharmonic functions on Ω, where u > 0 and v < +1, and let S(Ω) denote the collection of all subharmonic functions on Ω. We write Ω v Φu = fs 2 S(Ω) : s ≤ u − vg (the prefix Ω may be omitted where confusion is unlikely to occur), and will use this class to define the \partial reduction" of u with respect to v. If B is an open ball such that B ⊂ Ω, we denote by τBu the Poisson integral of u in B, and extend it to all of Ω by putting τBu = u elsewhere. v v Lemma 1. −v ≤ sup Φu 2 Φu. v v Proof. Clearly −v 2 Φu. The family Φu is locally uniformly bounded above since, if B is any open ball such that B ⊂ Ω, then s ≤ τBs ≤ τBu − infB v on B for v v every s 2 Φu. Let w denote the upper semicontinuous regularization of sup Φu. v Then w 2 S(Ω) and w ≥ sup Φu, with equality λ-almost everywhere (see Theorem 3.7.5 or 5.7.1 of [1]). It follows that w ≤ u − v almost everywhere, and hence, by v consideration of means over arbitrarily small balls, everywhere on Ω. Thus w 2 Φu, and the result follows. Next we define the partial reduction of u relative to v by Ω v v Pu = sup Φu + v; v where, again, the prefix Ω may be omitted. It is clear that 0 ≤ Pu ≤ u. Remark 2. If (vn) is an increasing sequence of superharmonic functions on Ω with vn v vn v limit v, then sup Φu # sup Φu and Pu ! Pu . To see this, we observe that the vn sequence (sup Φu ) of subharmonic functions decreases to a subharmonic limit w v v satisfying w ≥ sup Φu and, since w ≤ u − vn for each n, we also have w ≤ sup Φu. Let B(x; r) denote the open ball of centre x and radius r in RN . Lemma 3. If the superharmonic function v is continuous, then v (a) Pu is continuous, and v v (b) sup Φu is harmonic on the open set ! = fx 2 Ω: u(x) > Pu (x)g: Proof. (a) Let y 2 Ω and " > 0. Since τB(y,δ)v " v as δ # 0, it follows from Dini's theorem that we can choose η > 0 such that B(y; η) ⊂ Ω and (2) v − τB(y,η)v < " on Ω: PARTIAL BALAYAGE AND THE INVERSE PROBLEM OF POTENTIAL THEORY 3 v Let w = sup Φu. Then τB(y,η)w ≤ τB(y,η)(u − v) ≤ u − τB(y,η)v < u − v + " on Ω; v so τB(y,η)w − " 2 Φu and hence lim inf w(x) ≥ lim inf τB(y,η)w(x) − " = τB(y,η)w(y) − " ≥ w(y) − ": x!y x!y v Since " and y are arbitrary, w is lower (as well as upper) semicontinuous and so Pu is continuous. (The same argument shows more generally that, if v is continuous v on an open subset U of Ω, then Pu is also continuous on U.) v (b) Let B be any open ball such that B ⊂ ! and let " = infB(u − Pu ). It follows v from (a) that " > 0. Let w = sup Φu and y 2 B, and choose η > 0 such that v B(y; η) ⊂ B and (2) holds. Since u − v − w = u − Pu ≥ " on B, we have w ≤ τB(y,η)w ≤ τB(y,η)(u − v) − " ≤ u − τB(y,η)v − " < u − v on Ω: Since τB(y,η)w 2 S(Ω), it follows that τB(y,η)w = w. Hence w is harmonic on B(y; η), and (b) follows in view of the arbitrary choice of B and y. v Theorem 4. The function Pu is superharmonic on Ω. v Proof. In the case where v is continuous, we note from Lemma 3(b) that Pu is v superharmonic on !. Since Pu ≤ u on Ω with equality on Ωn!, we now see that v Pu is supermeanvalued at points of Ωn!. This, together with Lemma 3(a), shows v that Pu is superharmonic on all of Ω. In the general case we can find an increasing sequence (vn) of continuous su- vn perharmonic functions on Ω with limit v. The nonnegative functions Pu are su- vn v perharmonic, by the preceding paragraph, and Pu ! Pu by Remark 2. Hence v the lower semicontinuous regularization Pbu is superharmonic on Ω and coincides v v with Pu almost everywhere (λ) (see Corollary 5.7.2 in [1]). Since Pu is the sum of a subharmonic and a superharmonic function, consideration of means over arbitrarily v v v small balls now shows that Pbu = Pu everywhere, whence Pu is superharmonic on Ω. Lemma 5. (a) If (un) is an increasing sequence of superharmonic functions on Ω with limit u and, for each n, there is a superharmonic function wn such that u = u + w , then P v " P v. n n un u (b) If (un) is a decreasing sequence of superharmonic functions on Ω such that v v un # u quasi-everywhere, then Pu # Pu . n v v Ωn Ω (c) If (Ωn) is an exhaustion of Ω by open sets, then P u # P u. Proof. (a) Since P v − v − w 2 Φv , we see that u n un P v ≥ P v ≥ P v − w " P v quasi-everywhere on Ω: u un u n u The superharmonic functions lim P v and P v thus agree quasi-everywhere, n!1 un u and hence everywhere, on Ω. (b) The sequence (sup Φv ), of subharmonic functions on Ω, decreases to a sub- un harmonic function w on Ω. Since sup Φv ≤ u − v, we see that w ≤ u − v un n quasi-everywhere, and hence everywhere, on Ω. Thus w ≤ sup Φv ≤ sup Φv ! w as n ! 1; u un so P v # P v on Ω: un u 4 STEPHEN J GARDINER AND TOMAS SJODIN¨ v v v Ωn Ωm Ωn (c) If n ≥ m and s 2 Φu, then it is clear that sjΩm 2 Φu.
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